PHP验证表格

Question

我很难显示我在PHP教程中拨打printf中的输出。我刚刚遵循了本教程，但仍然无法弄清楚在Localhost中显示printf内部的变量有什么问题。有人可以帮助我吗？谢谢。

    <?php
            $name = '';
            $password = '';
            $gender = '';
            $color = '';
            $languages = [];
            $comments = '';
            $tc = '';
        
           if (isset($_POST['submit'])) {
                if (isset($_POST['name'])) {
                    $name = $_POST['name'];
                };
                if (isset($_POST['password'])) {  
                    $password = $_POST['password'];
                };
                if (isset($_POST['gender'])) {
                    $gender = $_POST['gender'];
                };
                if (isset($_POST['color'])) {
                    $color = $_POST['color'];
                };
                if (isset($_POST['languages'])) {
                    $languages = $_POST['languages'];
                };
                if (isset($_POST['comments'])) {
                    $comments = $_POST['comments'];
                };
                if (isset($_POST['tc'])) {
                    $tc = $_POST['tc'];
                };
            //here's the problem i cant resolve printing out the output//
            printf('User name: %s
                <br>Password: %s
                <br>Gender: %s
                <br>Color: %s
                <br>Language(s): %s
                <br>Comments: %s
                <br>T&amp;C: %s',
                htmlspecialchars($name, ENT_QUOTES),
                htmlspecialchars($password, ENT_QUOTES),
                htmlspecialchars($gender, ENT_QUOTES),
                htmlspecialchars($color, ENT_QUOTES),
                htmlspecialchars(implode('', $languages), ENT_QUOTES),
                htmlspecialchars($comments, ENT_QUOTES),
                htmlspecialchars($tc, ENT_QUOTES));
        
                
            }
        ?>
        
        
        <form action="" 
            method="post">
              User name:  <input type="text" name="name"><br>
              Password:  <input type="password" value="password"><br>
              Gender:
              <input type="radio" name="gender" value="f"> female
              <input type="radio" name="gender" value="m"> male
              <input type="radio" name="gender" value="o"> other<br/>
              Favorite color:
              <select name="color">
                <option value="">Please select</option>
                <option value="#f00">red</option>
                <option value="#0f0">green</option>
                <option value="#00f">blue</option>
        </select><br>
            Languages spoken:
            <select name="languages[]"multiple size="3">
                <option value="en">English</option>
                <option value="fr">French</option>
                <option value="it">Italian</option>
                </select><br>
                Comments: <textarea name="comments"></textarea><br>
            <input type="checkbox" name="tc" value="ok"> I accept the T&amp;C<br> 
        <input type="submit" value="Register">
        
        </form>`

Answer 1

此处的问题是如果（ISSET（$ _ post ['submit']））没有任何表格字段，即name submit，并且执行永远不会成立。 删除提交条件的if条件，否则将Sumbit按钮名称称为提交

<input type="submit" value="Register" name="submit">

Answer 2

您以前的代码中的错误是：

1. 如果语句结束之后，则不需要semicolons ;。
2. 没有名称属性为密码以表单中的输入指定。
3. 将表单数据的形式数据称为如果（isset（$ _ post ['submit']））{...}而无需在表单中指定name =“ submit”属性。
4. 爆破函数的使用无效，它将生成输出就像enfrit，反之亦然。

其他提示

5. 将必需的属性添加到每个输入以防止发送空形式数据。
6. 您已经在表单标签中指定method =“ post”，因此，无需验证每个输入字段为if（isset（$ _ post ['fieldName']）））{... }。 如果（ISSET（$ _ post ['submit']））{...}将以post方法发送所有表单数据。

最后，这是您的更新代码。

<?php

if (isset($_POST['submit'])) {
    $name = '';
    $password = '';
    $gender = '';
    $color = '';
    $languages = [];
    $comments = '';
    $tc = '';

    if (isset($_POST['name'])) {
        $name = $_POST['name'];
    }
    if (isset($_POST['password'])) {
        $password = $_POST['password'];
    }
    if (isset($_POST['gender'])) {
        $gender = $_POST['gender'];
    }
    if (isset($_POST['color'])) {
        $color = $_POST['color'];
    }
    if (isset($_POST['languages'])) {
        $languages = $_POST['languages'];
    }
    if (isset($_POST['comments'])) {
        $comments = $_POST['comments'];
    }
    if (isset($_POST['tc'])) {
        $tc = $_POST['tc'];
    }

    //print output
    printf('User name: %s
    <br>Password: %s
    <br>Gender: %s
    <br>Color: %s
    <br>Language(s): %s
    <br>Comments: %s
    <br>T & C: %s
    <br><br>',
    htmlspecialchars($name, ENT_QUOTES),
    htmlspecialchars($password, ENT_QUOTES),
    htmlspecialchars($gender, ENT_QUOTES),
    htmlspecialchars($color, ENT_QUOTES),
    htmlspecialchars(implode(', ', $languages), ENT_QUOTES),
    htmlspecialchars($comments, ENT_QUOTES),
    htmlspecialchars($tc, ENT_QUOTES));
}

?>

<form action="" method="post">
    User name: <input type="text" name="name">
    <br>
    Password: <input type="password" name="password">
    <br>
    Gender:
    <input type="radio" name="gender" value="f"> female
    <input type="radio" name="gender" value="m"> male
    <input type="radio" name="gender" value="o"> other
    <br>
    Favorite color:
    <select name="color">
        <option value="">Please select</option>
        <option value="#f00">red</option>
        <option value="#0f0">green</option>
        <option value="#00f">blue</option>
    </select>
    <br>
    Languages spoken:
    <select name="languages[]" multiple size="3">
        <option value="en">English</option>
        <option value="fr">French</option>
        <option value="it">Italian</option>
    </select>
    <br>
    Comments: <textarea name="comments"></textarea>
    <br>
    <input type="checkbox" name="tc" value="ok"> I accept the T & C
    <br>
    <input type="submit" name="submit" value="Register">
</form>