Swift-如何使用通用测试?
我想与仿制药一样 但是我想不出一种方式。
我的代码如下,我想测试零件准备()
。
class A_ViewModel {
var useCase: UseCaseProtocol = UseCase()
var item: A_CellModel = .init()
// I want to unittest prepare()
func prepare() {
// logic....
// and call calcuate
useCase.calculate(item: item)
}
}
protocol TestableProtocol {
var testProperty: Bool { get set }
}
class A_CellModel: TestableProtocol {
var testProperty: Bool = false
}
protocol UseCaseProtocol {
func calculate<T: TestableProtocol>(item: T)
}
class UseCase: UseCaseProtocol {
func calculate<T: TestableProtocol>(item: T) {
// logic......
}
}
但是,由于calcaulte(item:)
在USECase中使用通用,因此有必要移交清晰的类型(A_CELLMODEL)。
在这种情况下,A_ViewModel和A_CellModel之间存在依赖性,这使得很难测试该单元。
为了测试准备()
,carcaulte(item:)
放弃通用吗? 我应该使用存在类型吗?
I wanna unittest with generics.
But I can't think of a way.
My code is as below, and I want to test the part prepare()
.
class A_ViewModel {
var useCase: UseCaseProtocol = UseCase()
var item: A_CellModel = .init()
// I want to unittest prepare()
func prepare() {
// logic....
// and call calcuate
useCase.calculate(item: item)
}
}
protocol TestableProtocol {
var testProperty: Bool { get set }
}
class A_CellModel: TestableProtocol {
var testProperty: Bool = false
}
protocol UseCaseProtocol {
func calculate<T: TestableProtocol>(item: T)
}
class UseCase: UseCaseProtocol {
func calculate<T: TestableProtocol>(item: T) {
// logic......
}
}
However, since calcaulte(item:)
in usecase uses generic, it is necessary to hand over the clear type (A_CellModel).
In that case, there is a dependence between A_ViewModel and A_CellModel, which makes it difficult to test the unit.
In order to test prepare()
, should calcaulte(item:)
give up generic?
Should I use existential type?
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