Flutter分配通用未来< t>从函数回调
为什么不通用未来< t>
分配工作?我遇到了这个错误:类型'Future< t>?'的值无法分配给类型“未来< t>?”的变量。
typedef SimpleFutureFunction<T> = Widget Function(void Function(Future<T>? newFuture) onFuture);
class SimpleFuture<T> extends StatefulWidget {
const SimpleFuture({Key? key, required this.simple, this.future}) : super(key: key);
final SimpleFutureFunction simple;
final Future<T>? future;
@override
State<SimpleFuture> createState() => _SimpleFutureState();
}
class _SimpleFutureState<T> extends State<SimpleFuture<T>> {
Future<T>? _future;
@override
void initState() {
super.initState();
_future = widget.future;
}
@override
Widget build(BuildContext context) {
return widget.simple.call(<T>(Future<T>? newFuture) {
setState(() {
_future = newFuture;
});
});
}
}
Why does not generic Future<T>
assign work? i Get this error: A value of type 'Future<T>?' can't be assigned to a variable of type 'Future<T>?'.
typedef SimpleFutureFunction<T> = Widget Function(void Function(Future<T>? newFuture) onFuture);
class SimpleFuture<T> extends StatefulWidget {
const SimpleFuture({Key? key, required this.simple, this.future}) : super(key: key);
final SimpleFutureFunction simple;
final Future<T>? future;
@override
State<SimpleFuture> createState() => _SimpleFutureState();
}
class _SimpleFutureState<T> extends State<SimpleFuture<T>> {
Future<T>? _future;
@override
void initState() {
super.initState();
_future = widget.future;
}
@override
Widget build(BuildContext context) {
return widget.simple.call(<T>(Future<T>? newFuture) {
setState(() {
_future = newFuture;
});
});
}
}
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