开玩笑的魔术数量比较失败了... tobe

发布于 2025-02-12 15:37:27 字数 506 浏览 0 评论 0原文

我正在测试以确保buffer的魔术数字是zip格式。

我是通过提取缓冲区的第一个4个字节来串起的，并与pk的魔术数进行比较。

   const zipMagicNumber: string = 'PK'
   const uploadedMagicNumber: string = uploadMock.mock.calls[0][0].Body.subarray(0, 4).toString()

   expect(zipMagicNumber).toBe(uploadedMagicNumber)

但是测试失败了：

    expect(received).toBe(expected) // Object.is equality

    Expected: "PK"
    Received: "PK"

这些都是相同的值，并且都是字符串。我想念什么吗？

原文

I'm testing to ensure a Buffer's magic number is zip format.

I'm doing this by extracting the buffer's first 4 bytes to string and comparing against the magic number for zip which is PK.

   const zipMagicNumber: string = 'PK'
   const uploadedMagicNumber: string = uploadMock.mock.calls[0][0].Body.subarray(0, 4).toString()

   expect(zipMagicNumber).toBe(uploadedMagicNumber)

But the test is failing with:

    expect(received).toBe(expected) // Object.is equality

    Expected: "PK"
    Received: "PK"

These are the both the same values and are both strings. Am I missing something?

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等往事风中吹 2025-02-19 15:37:27

一些隐藏的字符引起了比较错误，因此，对于可读性，我移至使用十六进制比较，现在已经通过了：

const zipMagicNumber = Buffer.from('504B0304', 'hex').toString('hex')
const uploadedMagicNumber = uploadMock.mock.calls[0][0].Body.subarray(0, 4).toString('hex')

expect(zipMagicNumber).toBe(uploadedMagicNumber)

Some hidden characters were causing the comparison error, so for legibility I moved to using hex comparisons instead and now it's passing:

const zipMagicNumber = Buffer.from('504B0304', 'hex').toString('hex')
const uploadedMagicNumber = uploadMock.mock.calls[0][0].Body.subarray(0, 4).toString('hex')

expect(zipMagicNumber).toBe(uploadedMagicNumber)

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