Laravel将几秒钟转换为几小时和几分钟

发布于 2025-02-12 13:48:40 字数 1369 浏览 3 评论 0原文

我必须使用时间计算实现一些功能，并且我的应用具有以下类型的代码类型。

    date_default_timezone_set(auth()->user()->timezone);
                                        
        $t_now = \Carbon\Carbon::parse(date('Y-m-d H:i:s'));
                                        
$t_allowed = \Carbon\Carbon::parse($shift_details->start_time) ;
                                        
 @endphp
    
 @php
$check = $t_allowed->diffForHumans($t_now);
                                       
  $search = 'after';
 $dff_min = $t_allowed->diffInSeconds($t_now, true);
                                        
 $init = $dff_min;
 $day = floor($init / 86400);
 $hours = floor(($init - $day * 86400) / 3600);
 $minutes = floor(($init / 60) % 60);
 $seconds = $init % 60;
   $late_not_late = $hours . ' hours ' . $minutes . ' minutes ' . $seconds . ' seconds ';

首先，我想确认$ dff_min = $ t_lowered-＆gt; diffinseconds（$ t_now，true）;是返回分钟或秒吗？符合我的知识$ dff_min包含秒我知道可以使用（INIT/3600）计算时间，但是以下语句是什么意思是

$hours = floor(($init - $day * 86400) / 3600);

为什么开发人员减去$ DAY * 86400来自$ $ $ init ？

相似我们也可以计算秒$ in Init/60，因为一分钟内有60秒，但是跟随行的意思是什么

$minutes = floor(($init / 60) % 60);

，以及为什么他在这里使用Modulo

$seconds = $init % 60;

原文

I have to implement some functionality using time calculation and my app has following type of code.

    date_default_timezone_set(auth()->user()->timezone);
                                        
        $t_now = \Carbon\Carbon::parse(date('Y-m-d H:i:s'));
                                        
$t_allowed = \Carbon\Carbon::parse($shift_details->start_time) ;
                                        
 @endphp
    
 @php
$check = $t_allowed->diffForHumans($t_now);
                                       
  $search = 'after';
 $dff_min = $t_allowed->diffInSeconds($t_now, true);
                                        
 $init = $dff_min;
 $day = floor($init / 86400);
 $hours = floor(($init - $day * 86400) / 3600);
 $minutes = floor(($init / 60) % 60);
 $seconds = $init % 60;
   $late_not_late = $hours . ' hours ' . $minutes . ' minutes ' . $seconds . ' seconds ';

first i want to confirm that $dff_min = $t_allowed->diffInSeconds($t_now, true); is returning minutes or seconds? Acording to my knowledge $dff_min contain seconds
i know that hours could be calculate using (init /3600) but what is the meaning of following statement

$hours = floor(($init - $day * 86400) / 3600);

why developer subtracting $day * 86400 from $init?

similary we also can calculate seconds by $init/60 since in one minute there are 60 seconds but
what is meaning of following line

$minutes = floor(($init / 60) % 60);

and also why he is using Modulo here

$seconds = $init % 60;

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明明#如月 2025-02-19 13:48:40

\ Carbon \ Carbon :: Parse（date（'ymd H：i：s'））将两次致电Timelib并将失去微秒，只需做\ Carbon \ Carbon ::现在（），并且您无需重新发明轮子，您可以使用以下方式获得此精确的字符串：

$t_now = \Carbon\Carbon::now();
$t_allowed = \Carbon\Carbon::parse($shift_details->start_time);

$late_not_late = $t_allowed->diffForHumans($t_now, ['parts' => 3, 'syntax' => CarbonInterface::DIFF_ABSOLUTE]);

$ late_not_late将包含2天9小时20分钟

\Carbon\Carbon::parse(date('Y-m-d H:i:s')) will call twice the timelib and will loose the microseconds, just do \Carbon\Carbon::now() and you don't need to reinvent the wheel, you can get this exact string with:

$t_now = \Carbon\Carbon::now();
$t_allowed = \Carbon\Carbon::parse($shift_details->start_time);

$late_not_late = $t_allowed->diffForHumans($t_now, ['parts' => 3, 'syntax' => CarbonInterface::DIFF_ABSOLUTE]);

$late_not_late will contain 2 days 9 hours 20 minutes

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