如何创建空手道测试以验证WSDL文件

Question

我想确保我的WSDL合同没有变化，但是它对

  Scenario: Get demo.wsdl
    Given path '/demo'
    And param wsdl = 'demoLookup.wsdl'
    When method get
    Then status 200
    # note how we focus only on the relevant part of the payload and read expected XML from a file
    # And print 'response: ', response
    * def expected = read('expected-demo.wsdl')
    And match response contains expected

我收到

match failed: CONTAINS
  / | data types don't match (XML:LIST)
[60,119,115,100,108,58,100,101,10....

的文件的响应匹配，我假设这不是一个支持的功能，是否有任何解决方法，例如在RAW文件上匹配？

Answer 1

空手道对WSDL文件没有直接的支持。我个人的看法是，出于API端到端测试的目的，您不需要它。只需获取示例XML有效载荷并进行比较即可。这就是大多数团队所做的。

我还要补充说，根据我的经验，团队正在寻找捷径，例如期望WSDL或某种“模式”为他们进行所有辛勤工作。这总是很糟糕。您需要测试数据库状态，业务逻辑等。只是我的2 c。

Answer 2

如果其他人正在尝试类似的需求。

chksum.java

import org.springframework.util.StringUtils;
import java.util.zip.CRC32;

public class ChkSum {
    public static long generate(byte[] content){
        CRC32 crc32 = new CRC32();
        crc32.update(content, 0, content.length);
        return crc32.getValue();
    }

    public static int match(String expected, String actual){
        long exp_hash = generate(StringUtils.trimAllWhitespace(expected).getBytes());
        long act_hash = generate(StringUtils.trimAllWhitespace(actual).getBytes());

        return Long.compare(exp_hash,act_hash);
    }
}

功能

  Scenario: Get demo.wsdl
    * def chksum = Java.type('ChkSum')
    Given path '/demo'
    And param wsdl = 'demoLookup.wsdl'
    When method get
    Then status 200
    # note how we focus only on the relevant part of the payload and read expected XML from a file
    #And print 'response: ', response
    * xmlstring exp = read('expected-demo.wsdl')
    * xmlstring act = response
    * def result = chksum.match(exp, act)
    # And match exp == act
    And match result == 0