“加入Path”之间的区别和“/＆quot”在Pathlib中

发布于 2025-02-11 23:45:36 字数 333 浏览 1 评论 0原文

JOINPath与/code> pathlib模块中的操作员之间是否存在区别？该文档永远不会比较两种方法。本质上，这两个情况有所不同吗？

例子：


from pathlib import Path

foo = Path("some_path")
foo_bar_operator = foo / "bar"
foo_bar_joinpath = foo.joinpath("bar")

foo_bar_operator == foo_bar_joinpath
# Returns: True

原文

Is there a difference between joinpath and the / operator in the pathlib module? The documentation doesn't ever compare the two methods. Essentially are there any cases where these two are different?

Example:


from pathlib import Path

foo = Path("some_path")
foo_bar_operator = foo / "bar"
foo_bar_joinpath = foo.joinpath("bar")

foo_bar_operator == foo_bar_joinpath
# Returns: True

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娇纵 2025-02-18 23:45:36

没有区别。

    def joinpath(self, *args):
        """Combine this path with one or several arguments, and return a
        new path representing either a subpath (if all arguments are relative
        paths) or a totally different path (if one of the arguments is
        anchored).
        """
        return self._make_child(args)

    def __truediv__(self, key):
        try:
            return self._make_child((key,))
        except TypeError:
            return NotImplemented

”将多个参数传递到joinpath eg a.joinpath（b，c，d）。 / < / code>的等效词是a / b / c / d < / code>。

There is no difference. The source code confirms this:

    def joinpath(self, *args):
        """Combine this path with one or several arguments, and return a
        new path representing either a subpath (if all arguments are relative
        paths) or a totally different path (if one of the arguments is
        anchored).
        """
        return self._make_child(args)

    def __truediv__(self, key):
        try:
            return self._make_child((key,))
        except TypeError:
            return NotImplemented

Note you can pass multiple arguments to joinpath e.g. a.joinpath(b, c, d). The equivalent for / would be a / b / c / d.

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