如何在JQ中添加变量

发布于 2025-02-11 20:15:42 字数 1105 浏览 2 评论 0原文

我正在尝试在从JSON文件中获取信息时添加一个变量，如下所示。

stack=$(cat profiles.json | jq '.generic.category')

email=$(cat profiles.json | jq '.central.[Need to add $stack variable here].email')
echo $email
password=$(cat profiles.json | jq '.central.[Need to add $stack variable here].password')
echo $password

我尝试了一些事情，例如jq -arg v $ stack'.central [$ v] password*'，但它不起作用。

的样子。

  "central": {
        "one": {
            "tenant": "xxx-yyy-zzz",
            "email": "[email protected]",
            "password": "1111"
         },
        "two": {
            "tenant": "aaa-bbb-ccc",
            "email": "[email protected]",
            "password": "2222"
         }
  },
  "generic": {
        "username": "root",
        "password": "xyz",
        "project": "ABC",
        "category": "two"
    }

这就是我的个人资料

原文

I'm trying to add a variable while getting the info from a JSON file as shown below.

stack=$(cat profiles.json | jq '.generic.category')

email=$(cat profiles.json | jq '.central.[Need to add $stack variable here].email')
echo $email
password=$(cat profiles.json | jq '.central.[Need to add $stack variable here].password')
echo $password

I tried few things like jq --arg v $stack '.central[$v]password*' but it didnt work.

This is what my the profiles.json looks like:

  "central": {
        "one": {
            "tenant": "xxx-yyy-zzz",
            "email": "[email protected]",
            "password": "1111"
         },
        "two": {
            "tenant": "aaa-bbb-ccc",
            "email": "[email protected]",
            "password": "2222"
         }
  },
  "generic": {
        "username": "root",
        "password": "xyz",
        "project": "ABC",
        "category": "two"
    }

What is the right command to fetch the required information using the variable?

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酒绊 2025-02-18 20:15:42

$ cat profiles.json
{
   "central": {
        "one": {
            "tenant": "xxx-yyy-zzz",
            "email": "[email protected]",
            "password": "1111"
         },
        "two": {
            "tenant": "aaa-bbb-ccc",
            "email": "[email protected]",
            "password": "2222"
         }
  },
  "generic": {
        "username": "root",
        "password": "xyz",
        "project": "ABC",
        "category": "two"
    }
}

$ jq --arg MYVAR one '.central[$MYVAR].password' profiles.json
"1111"

$ cat profiles.json
{
   "central": {
        "one": {
            "tenant": "xxx-yyy-zzz",
            "email": "[email protected]",
            "password": "1111"
         },
        "two": {
            "tenant": "aaa-bbb-ccc",
            "email": "[email protected]",
            "password": "2222"
         }
  },
  "generic": {
        "username": "root",
        "password": "xyz",
        "project": "ABC",
        "category": "two"
    }
}

$ jq --arg MYVAR one '.central[$MYVAR].password' profiles.json
"1111"

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野の 2025-02-18 20:15:42

您可以在没有Shell变量stack的情况下执行，除非您想在Shell脚本的以后在不同的位置使用它。

email=$(jq -r '.central[.generic.category].email' profiles.json)
echo $email
password=$(jq -r '.central[.generic.category].password' profiles.json)
echo $password

You can do without the shell variable stack, unless you want to use it in different places later in your shell script.

email=$(jq -r '.central[.generic.category].email' profiles.json)
echo $email
password=$(jq -r '.central[.generic.category].password' profiles.json)
echo $password

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~没有更多了~