通过UDP发送腌制数据，UnicodeDecodeError失败了：＆＃x27; ascii＆＃x27;编解码器可以在位置0：序列不在范围内（128）中解释字节0xff

Question

这是我的代码片段，它将通过以太网从一台PC发送到另一台PC的数据效果很好。

import cv2, socket, pickle
import numpy as np
while True:
    ret, photo = cap.read()
    ret, buffer = cv2.imencode(".jpg",photo, [int(cv2.IMWRITE_JPEG_QUALITY),30])
    x_as_bytes = pickle.dumps(buffer)
    socket.sendto((x_as_bytes),(server_ip,server_port))

在接收器端，我无法解码它。它说：

Traceback (most recent call last):
    File "receive.py", line 12, in <module>
       data=pickle.loads(data)
UnicodeDecodeError: 'ascii' codec can't decode byte 0xff in position 0: ordinal not in range(128)

这是接收器端的片段

while True:
    x=s.recvfrom(1000000)
    clientip = x[1][0]
    data=x[0]
    print(data)
    data=pickle.loads(data) #ERROR IN THIS LINE
    print(type(data))
    data = cv2.imdecode(data, cv2.IMREAD_COLOR)
    cv2.imshow('server', data)
    if cv2.waitKey(10) == 13:
        break

Answer 1

您为什么还要腌制数据？无论如何，您都可以通过UDP发送二进制数据：

# Synthetic image
im = np.random.randint(0, 256,(480, 640, 3), dtype=np.uint8)

# JPEG encode
ret, buffer = cv2.imencode(".jpg", im, [int(cv2.IMWRITE_JPEG_QUALITY),30])

# Send
socket.sendto(buffer.tobytes(), (server_ip,server_port))

---

然后在接收端：

JPEG = s.recvfrom(1000000)
im = cv2.imdecode(np.frombuffer(JPEG, dtype=np.uint8), cv2.IMREAD_UNCHANGED)