存储器中的Swift Zipfoundation Drestrate String不起作用

发布于 2025-02-11 18:18:34 字数 477 浏览 1 评论 0原文

我在 https：//github.com/weichub.com/weichelb.com/weichsel/zipfoundation

我的要求是UNZIP内存中的文件内容并直接转换为字符串。

let archive = Archive(url: fileUrl, accessMode: .read, preferredEncoding: .utf8)
do{
   try archive?.extract(entry, consumer: {data in
      print(data.count)
    })
  }catch{}

档案对象始终无读取zip文件。另外，要提取方法的输入对象是什么？

原文

I am using ZipFoundation in Swift from https://github.com/weichsel/ZIPFoundation

My requirement is unzip the file contents in memory and directly convert into String.

let archive = Archive(url: fileUrl, accessMode: .read, preferredEncoding: .utf8)
do{
   try archive?.extract(entry, consumer: {data in
      print(data.count)
    })
  }catch{}

The archive object is always null its not reading zip file. Also what is the entry object to pass to extract method?

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如果没结果 2025-02-18 18:18:34

邮政基础档案支持订阅。这允许您通过archive通过存档[“ path/to/to/file.txt”]获得条目。

要访问获得的文件的内容，您可以使用extract的基于封闭的版本，如下所示：

guard let archiveURL = Bundle.main.url(forResource: "archive", withExtension: "zip"),
      let archive = Archive(url: archiveURL, accessMode: .read),
      let entry = archive["test/data.random"]
else { return }

_ = try? archive.extract(entry) { data in
    print(data.count)
}

ZIP Foundation archives support subscripting. This allows you to obtain an Entry by subscripting into an Archive via archive["path/to/file.txt"].

To get access to the contents of the obtained file, you use the closure-based version of extract as follows:

guard let archiveURL = Bundle.main.url(forResource: "archive", withExtension: "zip"),
      let archive = Archive(url: archiveURL, accessMode: .read),
      let entry = archive["test/data.random"]
else { return }

_ = try? archive.extract(entry) { data in
    print(data.count)
}

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