如何使用Grails中的字段插件渲染

发布于 2025-02-11 17:58:43 字数 1039 浏览 0 评论 0原文

我的代码：

hotelcontroller：

def search() {
    def result = Hotel.list()
    render(template: "searchTable", model: [hotelList: result], plugin: "fields")
}

views目录：

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错误消息：

URI
/hotel/search
Class
org.grails.web.servlet.mvc.exceptions.ControllerExecutionException
Message
null
Caused by
Unable to load template for uri [/hotel/_searchTable]. Template not found.

Around line 24 of grails-app\controllers\com\pool\HotelController.groovy
24:        render(template: "searchTable", model: [hotelList: result], plugin: "fields")

不应该这样：因为字段插件搜索/_ fields 目录

如果我尝试放置_searchtable.gsp /hotel目录中的模板 - 渲染方法像往常一样呈现＆lt; g：render＆gt;标签

编译：org.gerails.plugins：fields在build.gradle中

原文

My code:

HotelController:

def search() {
    def result = Hotel.list()
    render(template: "searchTable", model: [hotelList: result], plugin: "fields")
}

views directory:

templates directory:

Error message:

URI
/hotel/search
Class
org.grails.web.servlet.mvc.exceptions.ControllerExecutionException
Message
null
Caused by
Unable to load template for uri [/hotel/_searchTable]. Template not found.

Around line 24 of grails-app\controllers\com\pool\HotelController.groovy
24:        render(template: "searchTable", model: [hotelList: result], plugin: "fields")

Should not be like that because fields plugin searches templates in /templates/_fields directory

If I try to place _searchTable.gsp template in /hotel directory - render method renders it as usual <g:render> tag

compile: org.gerails.plugins:fields is in build.gradle of course

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