从本地iOS调用扑动，并使用鸽子flutterapi恢复价值
我正在使用 pigeon 库库来连接颤音和本机平台代码，尤其是iOS，特别是swift。
我想从Swift调用弹奏函数，并同步获得值。
颤动上的函数是这样的：
@FlutterApi()
abstract class MyFlutterApi {
String? didSyncFunctionCalled();
}
此处的Swift代码：
let flutterApi: MyFlutterApi?
public func callSyncFunction() -> String? {
flutterApi?.didSyncFunctionCalled(completion: { (value: String?, error: Error?) in
return value
})
}
您可以看到该函数返回字符串（无效），并且我需要从flutter中的字符串。
此实现是不正确的。我得到 error 来自return> return> return value value - ＆gt; 无法转换类型的“字符串？”的值。要封闭结果类型“ void”
从我所理解的内容中，Pigeon总是在错误的情况下生成代码，并最终返回。
这是我不想使用的解决方案：
public func callSyncFunction(completion: @escaping (String?) -> Void) {
flutterApi?.didSyncFunctionCalled(completion: { (value: String?, error: Error?) in
completion(value)
})
}
是否有一种可以在本机代码中使用这样使用的函数的方法？
public func callSyncFunction() -> String? {
let value: String? = flutterApi?.didSyncFunctionCalled()
return value
}
I'm using Pigeon library to connect Flutter and native platform code, in particular iOS with Swift.
I want to call a flutter function from Swift and get a value back, all synchronously.
The function on flutter is defined like this:
@FlutterApi()
abstract class MyFlutterApi {
String? didSyncFunctionCalled();
}
Here the Swift code:
let flutterApi: MyFlutterApi?
public func callSyncFunction() -> String? {
flutterApi?.didSyncFunctionCalled(completion: { (value: String?, error: Error?) in
return value
})
}
As you can see the function returns a string (nullable) and I need that string from flutter.
This implementation is incorrect. I get an error from XCode on the line of return value -> Cannot convert value of type 'String?' to closure result type 'Void'
From what I understood, Pigeon always generates code with completion closure with error and eventually a value to return.
This is the solution I don't want to use:
public func callSyncFunction(completion: @escaping (String?) -> Void) {
flutterApi?.didSyncFunctionCalled(completion: { (value: String?, error: Error?) in
completion(value)
})
}
Is there a method to define functions that can be used like this in native code?
public func callSyncFunction() -> String? {
let value: String? = flutterApi?.didSyncFunctionCalled()
return value
}
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评论（1）
您仅同步返回数据，来自API的请求是异步。
所有这些都是基于方法渠道构建的，因此异步功能并没有消除更多的包装。
You only return data synchronously the requests from the API is async.
It is all built on MethodChannels so the async functionality did not dissapear its more of wrapped up.