动态保存到CSV使用数组

Question

我正在使用CSV模块将数组保存到CSV，但是我想使其更具动态性。抱歉，如果这已经在这里，我尝试搜索，但无济于事。 这是我当前的代码，它运行良好。...

filename = 'zeroTime_.csv'        #save to csv
f = open(filename, "w")
f.write("{},{},{},{}\n".format("R[0]", "F[0]","R[1]", "F[1]"))
for x in zip(R[0], F[0],R[1], F[1]):
    f.write("{},{},{},{}\n".format(x[0], x[1], x[2], x[3]))
f.close()

但是我想制作，以便如果Array R有超过2列，它仍然可以正常工作 我尝试创建“ r [0]”，“ f [0]”，“ r [1]”，“ f [1]”作为字符串，但不喜欢它，我的代码为每个通道 r r f 由numch：

for x in range(NumCh):
    title = title +'"R['+str(x)+']",'+'"F['+str(x)+']",'
    bracket = bracket + '{},{},'
title = title[:-1]
bracket = bracket[:-1]
bracket = bracket + '\n"'

filename = 'zeroTime_.csv'        #save to csv
f = open(filename, "w")
f.write(bracket.format(title))
for x in zip(R[0], F[0],R[1], F[1]):
    f.write(bracket.format(x[0], x[1], x[2], x[3]))
f.close()

给我错误：（

Traceback (most recent call last):
  File "base.py", line 8, in <module>
    b = pd.proc(NumCh, a)
  File "C:\Users\jtpkalaverick\Documents\Python\module\time_proc.py", line 24, in proc
    f.write(bracket.format(title))
IndexError: Replacement index 1 out of range for positional args tuple

我正在模块中运行它以pd。）

编辑（30.06.22）

我有2个模块tick_proc，该模块会产生一些任意的数组和time_proc，并且在数组上可以做一些基本的数学。 Numch和样本传递到模块中，只是INTS

主代码：

import tick_proc as tp
import time_proc as pd
NumCh = 2
samples = 10

a = tp.collect_data(NumCh, samples)
b = pd.proc(NumCh, a)
print('b', b)

tick Proc：

print('Importing module "TickProc"')
R = []
F = []
def collect_data(NumCh, samples):
    for x in range(NumCh):
        R.append([])
        F.append([])

    for x in range(NumCh):
        for y in range(samples):
            R[x].append(y*x)
            F[x].append(y*x -1)

    return F, R

time_proc： time_proc：

import csv
def proc(NumCh, a):
    R = a[0]
    F = a[1]
    T = []
    bracket = '"'
    title = ''
    vars = ''

    for x in range(NumCh):
        T.append([])
        title = title +'"R['+str(x)+']",'+'"F['+str(x)+']",'
        bracket = bracket + '{},{},'
    title = title[:-1]
    bracket = bracket[:-1]
    bracket = bracket + '\n"'
    print(bracket)
    print(title)
    for i in range(NumCh):
        for j in range(len(R[i])):
            T[i].append(R[i][j]-F[i][j])

    filename = 'zeroTime_.csv'        #save to csv
    f = open(filename, "w")
    f.write(bracket.format(title))
    for x in zip(R[0], F[0],R[1], F[1]):
        f.write(bracket.format(x[0], x[1], x[2], x[3]))
    f.close()
    return T