HTML5捕获背面摄像头
我正在尝试从后面的摄像头捕获图像，代码按预期工作，手机在正面或背面打开，但是使用后面的摄像头，我得到了空的$ _files [“ filetoupload”]到PHP文件。如果我使用前置摄像头，则$ _files [“ filetoupload”] [“ tmp_name”]值将按预期提供给PHP文件。
<!DOCTYPE html>
<html>
<body>
<form action="upload.php" method="post" enctype="multipart/form-data">
Select image to upload:
<input type="file" name="fileToUpload" id="fileToUpload" accept="image/*" capture="environment">
<input type="submit" value="Upload Image" name="submit">
</form>
</body>
</html><?php
$target_dir = "uploads/";
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
echo $target_file.'<br>';
$uploadOk = 1;
$imageFileType = strtolower(pathinfo($target_file,PATHINFO_EXTENSION));
// Check if image file is a actual image or fake image
if(isset($_POST["submit"])) {
$check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
echo 'check '.$check;
if($check !== false) {
echo "File is an image - " . $check["mime"] .$_FILES["fileToUpload"]["tmp_name"];
$uploadOk = 1;
} else {
echo "File is not an image.";
$uploadOk = 0;
}
}
// Check if $uploadOk is set to 0 by an error
if ($uploadOk == 0) {
echo "Sorry, your file was not uploaded.";
// if everything is ok, try to upload file
} else {
if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file)) {
echo "The file ". htmlspecialchars( basename( $_FILES["fileToUpload"]["name"])). " has been uploaded.";
} else {
echo "Sorry, there was an error uploading your file.";
}
}
?>I am trying to capture an image from the back facing camera, the code works as expected the phone opens in either front or back, but using the back facing camera I get empty $_FILES["fileToUpload"]["tmp_name"] value passed to the php file. If I use the front facing camera a $_FILES["fileToUpload"]["tmp_name"] value is supplied to the php file as expected.
<!DOCTYPE html>
<html>
<body>
<form action="upload.php" method="post" enctype="multipart/form-data">
Select image to upload:
<input type="file" name="fileToUpload" id="fileToUpload" accept="image/*" capture="environment">
<input type="submit" value="Upload Image" name="submit">
</form>
</body>
</html><?php
$target_dir = "uploads/";
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
echo $target_file.'<br>';
$uploadOk = 1;
$imageFileType = strtolower(pathinfo($target_file,PATHINFO_EXTENSION));
// Check if image file is a actual image or fake image
if(isset($_POST["submit"])) {
$check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
echo 'check '.$check;
if($check !== false) {
echo "File is an image - " . $check["mime"] .$_FILES["fileToUpload"]["tmp_name"];
$uploadOk = 1;
} else {
echo "File is not an image.";
$uploadOk = 0;
}
}
// Check if $uploadOk is set to 0 by an error
if ($uploadOk == 0) {
echo "Sorry, your file was not uploaded.";
// if everything is ok, try to upload file
} else {
if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file)) {
echo "The file ". htmlspecialchars( basename( $_FILES["fileToUpload"]["name"])). " has been uploaded.";
} else {
echo "Sorry, there was an error uploading your file.";
}
}
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要回答我自己的问题max_file_size需要在php.ini文件中进行编辑以从默认的2M增加文件大小
To answer my own question max_file_size upload needed to be edited in the php.ini file to increase the file size from the default 2m