如何在角度以不同格式构造对象

Question

我是新来的角。我正在尝试重组我从API响应中获得的对象。我需要将当前对象构造为所需的对象。

这是下面的当前对象

let temp = {
"imagesList": {
    "de": [{
       "path": "",
       "text": "desc text"
     },
     {
       "path": "",
       "text": "desc text"
     }],
     "en": [{
       "path": "",
       "text": "desc text"
     }]
   }
}

是所需的对象，从上面定义的当前对象

let temp = [
    {
      "path": "",
      "description": [
        {
          "language": "en",
          "text": "desc text"
        }
      ]
    },
    {
      "path": "",
      "description": [
        {
          "language": "de",
          "text": "desc text"
        }
      ]
    },
    {
      "path": "",
      "description": [
        {
          "language": "de",
          "text": "desc text"
        }
      ]
    }, 
 
  ]

如何使用Angular中的Typescript实现此目标。 沙盒 link 提前致谢

Answer 1

在这里，您有解决方案：

 ngOnInit() {
    console.log(this.temp);
    const transformed: any[] =[]; 

    for (const key in this.temp.imagesList) {
      if (this.temp.imagesList.hasOwnProperty(key)) {
          for(const o of this.temp.imagesList[key]){
            transformed.push({
              path:o.path,
              description:[{
                language:key,
                text:o.text
              }]
            });
          }
      }
    }
    console.log(transformed);
  }

顺便说一句：您将使用JavaScript完全相同。这并不是真正的角度或打字稿问题；