计算一列日期计数

发布于 2025-02-11 06:37:03 字数 293 浏览 0 评论 0原文

我想计算人们拥有的日期（或访问）数量（或访问）的平均值和标准偏差。示例数据为：

id   date
1    2015-02-23
1    2015-04-24
2    2018-05-23
2    2022-12-05
2    2022-12-06
3    2021-05-21

ID1有2次访问（由2个日期证明），ID2有3次访问，ID3有1次访问，因此平均值为（2+3+1）/3 = 2。

有人知道如何计算平均值和标准偏差吗？我尝试使用总结函数来执行此操作，但我无法正常工作。

原文

I want to calculate the mean and standard deviation for the number of dates (or visits) that people have. Sample data are:

id   date
1    2015-02-23
1    2015-04-24
2    2018-05-23
2    2022-12-05
2    2022-12-06
3    2021-05-21

ID1 has 2 visits (evidenced by 2 dates), ID2 has 3 visits, and ID3 has 1 visit, so the mean would be (2+3+1)/3 =2.

Does anyone know how to calculate the mean and standard deviation? I tried to do this using the summarize function, but I can't get it to work.

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梦里寻她 2025-02-18 06:37:03

您可以使用rle函数与ID

数据

df < - structure(list(id = c(1L, 1L, 2L, 2L, 2L, 3L), date = c("2015-02-23", 
"2015-04-24", "2018-05-23", "2022-12-05", "2022-12-06", "2021-05-21"
)), class = "data.frame", row.names = c(NA, -6L))

mean(rle(df$id)$lengths)

You can use rle function with your id

data

df < - structure(list(id = c(1L, 1L, 2L, 2L, 2L, 3L), date = c("2015-02-23", 
"2015-04-24", "2018-05-23", "2022-12-05", "2022-12-06", "2021-05-21"
)), class = "data.frame", row.names = c(NA, -6L))