查找重复并分别翻转它们

Question

df[0] = [0.0000000,0.0082707,0.0132000, 0.0255597, 0.0503554, 0.0751941, 0.1000570, 0.1498328, 0.1996558, 0.2495240, 0.2994312, 0.3993490, 0.4993711, 0.5994664, 0.6996058, 0.7997553, 0.8998927, 0.9499514, 1.0000000, 0.0000000, 0.006114 , 0.0062188, 0.0087532, 0.0138088, 0.0264052, 0.0515127, 0.0765762, 0.1016176, 0.1516652, 0.2016828, 0.2516733, 0.3016387, 0.4015163, 0.5013438, 0.6011363, 0.7008976, 0.8006328, 0.9003380, 0.9501740, 1.0000000]

df[1] = [0.00000，0.0233088，0.0298517，0.0425630，0.0603942，0.0739301，0.0850687，0.1023515，0.1149395，0.1149395，0.1230325，0.1230325，0.1272298，0.1272298，0.12253360,3333333533335333533333353335333335333353335333335333355 0445423、0.0207728、0.0098870、0.0000000、0.0000000，-.0208973，-.0210669，-.0210669， -.0247377, -.0307807, -.0416431, -.0548774, -.0637165, -.0703581, -.0801452, -.0869356, -.0910290, -.0926252, -.0905235, -.0834273, -. 0728351，-.0591463，-.0428603，-.0235778，-.0122883，0.0000000]

您可以使python代码在df [0] df [0]和Lets中检测到一定数量的零数在此示例中说，如果它检测到三个或更多零在中间翻转阵列？因此，它看起来像df [0] = [0.00000,0.0082707,0.0132000，0.0255597，0.0503554，0.0751941，0.1000570，0.1498328，0.1498328 994664，0.6996058，0.7997553，0.8998927，0.9499514，1.0000000 , 1.0000000, 0.950174, 0.900338, 0.8006328, 0.7008976, 0.6011363, 0.5013438, 0.4015163, 0.3016387, 0.2516733, 0.2016828, 0.1516652, 0.1016176, 0.0765762, 0.0515127, 0.0264052, 0.0138088, 0.0087532 ,0.0062188, 0.006114, 0.0000000] 以及Flip df [1]尊重df [0]

Answer 1

discont = np.diff(df[0]).argmin()
x1 = df[0][:discont+1]
x1 = np.array(x1)

y1 = df[1][:discont+1]

x2 = df[0][discont+1:]
x2 = np.array(x2)

y2 = df[1][discont+1:]
y2 = np.array(y2)

x_flip = np.flip(x2)
y_flip = np.flip(y2)

x = np.concatenate((x1,x_flip))
y = np.concatenate((y1,y_flip))