无法使用getx颤动来发起列表

发布于 2025-02-11 04:18:05 字数 1316 浏览 1 评论 0原文

我有一个列表，我想通过从数据库中获取数据来启动它。出现此错误消息

[GET]已检测到GetX的不当使用。您只能将GETX或OBX用于将要更新的特定小部件。如果您看到此错误，您可能没有将任何可观察的变量插入GetX/obx 或将它们插入getx认为适合更新的范围之外（示例：getx =＆gt; heidewidget =＆gt; variable observable）。如果您需要更新父窗口小部件和子小部件，请将每个小部件包装在OBX/GETX中。

class PasswordController extends GetxController {
   final passwordsList = <Password>[].obs;

   final db = Dao.instance;

Future<void> initilizePasswordsList() async {
   final passwords = await db.getAllPasswords();
   passwordsList.addAll([...passwords]);
   return;
}
}

    Future<void> main() async {
    final passwordController = Get.put(PasswordController());
    await passwordController.initilizePasswordsList();

    runApp(const MyApp());
    }

  const PasswordsList({super.key});

  @override
  Widget build(BuildContext context) {
    return GetX<PasswordController>(
      builder: (controller) {
        return ListView(
          children: controller.passwordsList
              .map((e) => Obx(
                    () => PasswordTile(
                      password: e.password,                     
                      websiteName: e.websiteName,
                    ),
                  ))
              .toList(),
        );
      },
    );
}
}

原文

I have a list and I want to initilize it by getting the data from the database. and this error message appears

[Get] the improper use of a GetX has been detected.
You should only use GetX or Obx for the specific widget that will be updated.
If you are seeing this error, you probably did not insert any observable variables into GetX/Obx
or insert them outside the scope that GetX considers suitable for an update
(example: GetX => HeavyWidget => variableObservable).
If you need to update a parent widget and a child widget, wrap each one in an Obx/GetX.

class PasswordController extends GetxController {
   final passwordsList = <Password>[].obs;

   final db = Dao.instance;

Future<void> initilizePasswordsList() async {
   final passwords = await db.getAllPasswords();
   passwordsList.addAll([...passwords]);
   return;
}
}

    Future<void> main() async {
    final passwordController = Get.put(PasswordController());
    await passwordController.initilizePasswordsList();

    runApp(const MyApp());
    }

  const PasswordsList({super.key});

  @override
  Widget build(BuildContext context) {
    return GetX<PasswordController>(
      builder: (controller) {
        return ListView(
          children: controller.passwordsList
              .map((e) => Obx(
                    () => PasswordTile(
                      password: e.password,                     
                      websiteName: e.websiteName,
                    ),
                  ))
              .toList(),
        );
      },
    );
}
}

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榕城若虚 2025-02-18 04:18:05

在listView中删除obx e 是不可观察的，password> passwordlist是。您已经在使用getx观察它。因此，您的listView应该看起来像：

ListView(
      children: controller.passwordsList
          .map((e) => PasswordTile(
                  password: e.password,                     
                  websiteName: e.websiteName,
                ),
              )
          .toList(),
    );

Remove the Obx inside the ListView as e is not observable, passwordList is. And you are already observing it with GetX. Therefore your ListView should look like:

ListView(
      children: controller.passwordsList
          .map((e) => PasswordTile(
                  password: e.password,                     
                  websiteName: e.websiteName,
                ),
              )
          .toList(),
    );

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