Python：请求有效的urllib3错误

Question

我有以下代码

http = urllib3.PoolManager()
resp = http.request(
    "GET",
    "https://api.nhs.uk/medicines/aciclovir",
    headers={
        "subscription-key":"XXX"
    }
)
print(resp.data)

响应是：

You don't have permission to access "http://api.nhs.uk/medicines/aciclovir" on this server

为什么它转到http：//地址？

但是，当我使用下面的请求时，

url = "https://api.nhs.uk/medicines/aciclovir"

payload={}
headers = {
  'subscription-key': 'XXX'
}

response = requests.request("GET", url, headers=headers, data=payload)

print(response.text)

有什么建议是成功的吗？

更新1

这是正在执行错误发生的确切代码，是的，它确实显示了http：// error

更新2

urllib3

Listening on 0.0.0.0 7777
Connection received on *** 50054
GET / HTTP/1.1
Host: ***:7777
Accept-Encoding: identity
subscription-key: xxx
User-Agent: python-urllib3/1.26.9

请求

Listening on 0.0.0.0 7777
Connection received on *** 50095
GET / HTTP/1.1
Host: ***:7777
User-Agent: python-requests/2.28.0
Accept-Encoding: gzip, deflate
Accept: */*
Connection: keep-alive
subscription-key: xxx

Answer 1

感谢 https://stackoverflow.com/users/240443/amadan 问题是服务器不喜欢服务器Urllib3提供的默认用户代理字符串

更改它，甚至只是分解python-urllib字符串，例如pyxthon-urllib使它起作用，

我在他们的支持下进行了此操作