如何在列表中分组直到找到某个元素？

Question

会尽力解释这一点。

目前，我正在刮擦硒。我只是想从页面上获得和弦，所以我使用此代码：

for elem in driver.find_elements_by_xpath('.//span[@class = "_3PpPJ OrSDI"]'):
    print (elem.text)

但这使它们在长列表中打印。

问题是我需要按照网站上的方式进行组织。

例如：

[ Verse 1 ] 
G Em C G
[ Verse 2 ]
G Em C G 

这样：

我不确定是否应该使用sufter-sibling或什么。我的完整代码在这里bellow：

from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.chrome.service import Service
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.chrome.options import Options
from selenium_stealth import stealth
from fake_useragent import UserAgent
from bs4 import BeautifulSoup as BS
import pandas as pd
import time
from collections import Counter
import undetected_chromedriver as uc
from selenium import webdriver
from cleantext import clean
from selenium.common.exceptions import NoSuchElementException
from selenium.webdriver.support import expected_conditions as EC

options = Options() 
#options.headless = True
options.add_argument("start-maximized")
options.add_argument('--no-sandbox') 
driver = uc.Chrome(options=options)

url6 = 'https://tabs.ultimate-guitar.com/tab/olivia-rodrigo/drivers-license-chords-3504560'

driver.get(url6)
driver.implicitly_wait(30)

try:
    verse_1 = driver.find_element_by_xpath("// span[contains(text(),\
    '[Verse 1]')]").text
    print(verse_1)
except NoSuchElementException:
        time.sleep(1)

for elem in driver.find_elements_by_xpath('.//span[@class = "_3PpPJ OrSDI"]'):
    print (elem.text)            

verse_2 = driver.find_element_by_xpath("// span[contains(text(),\
'[Verse 2]')]").text
print(verse_2)

Answer 1

我更改了您的代码。这应该从开箱即用：

from selenium import webdriver
from selenium.webdriver.chrome.service import Service
from webdriver_manager.chrome import ChromeDriverManager
from selenium.webdriver.common.by import By

driver = webdriver.Chrome(service=Service(ChromeDriverManager().install()))

url6 = 'https://tabs.ultimate-guitar.com/tab/olivia-rodrigo/drivers-license-chords-3504560'

driver.get(url6)
driver.implicitly_wait(30)

list_verses = []
for x in driver.find_elements(by=By.XPATH, value="//span[contains(text(),'[Verse')]"):
    list_verses.append(x.text)

dict_attributes= {}
for x in list_verses:
    new_attr = []
    for elem in driver.find_elements(by=By.XPATH, value="//span[contains(text(),'{0}')]/following-sibling::span/span/span[@class = '_3PpPJ OrSDI']".format(x)):
        new_attr.append(elem.text)
    dict_attributes[x] = new_attr
for x in list_verses:
    print(x)
    print(", ".join(dict_attributes[x]))

这是输出：

[Verse 1]
G, Em, C, G, G, Em, C, G, C, G, C, G, Em, D, G, Bm7, C, C6, D, G, G, Em, C, G, C, G, C, G, Em, D, G, Bm7, C, C6, D, G, G, D/F#, Em, C, G, D, Em, C, G, D, Em, C, G, D, Em, C, G, D, C, G, C, G, Em, D, Bm7, D, C, C6, D, G, C, D, Em7
[Verse 2]
G, Em, C, G, C, G, C, G, Em, D, G, Bm7, C, C6, D, G, G, Em, C, G, C, G, C, G, Em, D, G, Bm7, C, C6, D, G, G, D/F#, Em, C, G, D, Em, C, G, D, Em, C, G, D, Em, C, G, D, C, G, C, G, Em, D, Bm7, D, C, C6, D, G, C, D, Em7
[Verse 3]
G, Em, C, G, C, G, C, G, Em, D, G, Bm7, C, C6, D, G, G, D/F#, Em, C, G, D, Em, C, G, D, Em, C, G, D, Em, C, G, D, C, G, C, G, Em, D, Bm7, D, C, C6, D, G, C, D, Em7