如何使用Urllib或Shutil将图像下载到特定的本地目录？

发布于 2025-02-10 20:46:31 字数 984 浏览 1 评论 0原文

我使用slutil从URL下载图像，它可以正常工作，但它在项目目录上下载了图像。是否可以指定目录以使程序将其保存在那里？

我在Stackoverflow上搜索了一个解决方案，但仅使用Urllib urlretrieve找到了一个解决方案，该解决方案与我要做的事情并不相关。谢谢

import requests
import shutil
import os
import urllib.request

url = "https://www.lamborghini.com/sites/it-en/files/DAM/lamborghini/facelift_2019/homepage/families-gallery/2022/04_12/family_chooser_tecnica_m.png"

file_name = input("save image as :")
file_name += ".jpg"

res = requests.get(url, stream = True)
if res.ok:
    with open(file_name,"wb") as f:
        shutil.copyfileobj(res.raw,f)
    print("image succesfully downloaded ", file_name)
else:
    print("Download failed: status code {}\n{}".format(res.status_code, res.text))

或使用Urllib


f = open("sadasd.png", "wb")
f.write(urllib.request.urlopen(r"https://www.lamborghini.com/sites/it-en/files/DAM/lamborghini/facelift_2019/homepage/families-gallery/2022/04_12/family_chooser_tecnica_m.png").read())
f.close()

原文

I used shutil to download an image from an URL and it works fine but it downloads the images on the project directory. Is it possible to specify a directory so that the program saves it there?

I searched for a solution on StackOverflow but only found a solution using urllib urlretrieve which does not really relate to what I am trying to do. Thank you

import requests
import shutil
import os
import urllib.request

url = "https://www.lamborghini.com/sites/it-en/files/DAM/lamborghini/facelift_2019/homepage/families-gallery/2022/04_12/family_chooser_tecnica_m.png"

file_name = input("save image as :")
file_name += ".jpg"

res = requests.get(url, stream = True)
if res.ok:
    with open(file_name,"wb") as f:
        shutil.copyfileobj(res.raw,f)
    print("image succesfully downloaded ", file_name)
else:
    print("Download failed: status code {}\n{}".format(res.status_code, res.text))

or using urllib


f = open("sadasd.png", "wb")
f.write(urllib.request.urlopen(r"https://www.lamborghini.com/sites/it-en/files/DAM/lamborghini/facelift_2019/homepage/families-gallery/2022/04_12/family_chooser_tecnica_m.png").read())
f.close()

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信仰 2025-02-17 20:46:31

我找到了一个简单的解决方案。因此，我将代码更改为仅使用Urllib。我缺少的是目标路径末端的前向斜线，即C：用户\ User \ Pictures \ test/。

为了添加另一个信息，您可以在“代码块”中看到的，使用第二个参数作为要保存的位置。

导入Urllib.Request

def download_jpg(url, file_path, file_name):
    full_path = file_path + file_name + ".jpg"
    urllib.request.urlretrieve(url, full_path)


url = input("Enter img URL to download: ")
file_name = input("Enter file name to save as: ")

download_jpg(url, r"C:\Users\User\Pictures\test/", file_name )

I found a simpler solution. So I changed my code to use only Urllib. What I was missing was the forward slash at the end of the destination path which is C:users\user\Pictures\test/.

To add another piece of information as you can see in the code block urlretrieve uses the second argument as a location that you want to save.

import urllib.request

def download_jpg(url, file_path, file_name):
    full_path = file_path + file_name + ".jpg"
    urllib.request.urlretrieve(url, full_path)


url = input("Enter img URL to download: ")
file_name = input("Enter file name to save as: ")

download_jpg(url, r"C:\Users\User\Pictures\test/", file_name )

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