更改追溯（最新通话最后）显示“错误：网站不可用”

发布于 2025-02-10 20:38:55 字数 847 浏览 1 评论 0原文

我发现Python是一种爱好，所以现在我正在尝试解决问题。

当网站不响应（HTTP错误503：不可用的服务）时，我会知道

Traceback (most recent call last):
  File "c:\Users\dawid\Studia\Programowanie\HTML.py", line 30, in <module>
    start()
  File "c:\Users\dawid\Studia\Programowanie\HTML.py", line 21, in start
    response = browser.open(oceny)
  File "C:\Users\dawid\Studia\Programowanie\.venv\lib\site-packages\mechanize\_mechanize.py", line 257, in open
    return self._mech_open(url_or_request, data, timeout=timeout)
  File "C:\Users\dawid\Studia\Programowanie\.venv\lib\site-packages\mechanize\_mechanize.py", line 313, in _mech_open
    raise response
mechanize._response.get_seek_wrapper_class.<locals>.httperror_seek_wrapper: HTTP Error 503: Service Unavailable

如何更改它以显示诸如“有HTTP错误：503-等待几分钟”之类的内容？

原文

I found Python as a hobby so now I'm trying to fix a problem.

When a website is not responding (HTTP Error 503: Service Unavailable), I get

Traceback (most recent call last):
  File "c:\Users\dawid\Studia\Programowanie\HTML.py", line 30, in <module>
    start()
  File "c:\Users\dawid\Studia\Programowanie\HTML.py", line 21, in start
    response = browser.open(oceny)
  File "C:\Users\dawid\Studia\Programowanie\.venv\lib\site-packages\mechanize\_mechanize.py", line 257, in open
    return self._mech_open(url_or_request, data, timeout=timeout)
  File "C:\Users\dawid\Studia\Programowanie\.venv\lib\site-packages\mechanize\_mechanize.py", line 313, in _mech_open
    raise response
mechanize._response.get_seek_wrapper_class.<locals>.httperror_seek_wrapper: HTTP Error 503: Service Unavailable

How can I change it to display something like "There is a HTTP Error: 503 - wait a few minutes"?

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盛夏已如深秋| 2025-02-17 20:38:55

最好的方法是使用try-except。

语法非常容易：

try:
    # code that throws exception here
except:
    print("There is a HTTP Error: 503 - wait a few minutes")

如果您可能需要处理不同的异常，则可以将特定的异常和错误添加到除外。如果离开空白，您将处理每个错误。
如果您必须在例外加薪后要关闭连接，则可以添加最后。

try:
    # code that throws exception here
except:
    print("There is a HTTP Error: 503 - wait a few minutes")
finally:
    # code that closes everything safely

The best way to do this is using a try-except.

The syntax is pretty easy:

try:
    # code that throws exception here
except:
    print("There is a HTTP Error: 503 - wait a few minutes")

You can add specific Exceptions and Errors into the except clause, if you maybe have to handle different exceptions. If left blank, you will handle every error.
In case, you can also add a finally if you have to close a connection after the exception raise,, like so:

try:
    # code that throws exception here
except:
    print("There is a HTTP Error: 503 - wait a few minutes")
finally:
    # code that closes everything safely

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