Kotlin（Intellij）中的NumberFormateXception
这是我想做的，我希望用户输入任何数字，并且应该显示它，但是我会遇到此错误。 导入java.util。*
这是我的代码
fun main(){
print("Enter your age")
var age = readLine()!!.toInt()
print(age)
}
，我遇到的错误是
Enter your age 40
Exception in thread "main" java.lang.NumberFormatException: For input string: " 40"
at java.base/java.lang.NumberFormatException.forInputString(NumberFormatException.java:67)
at java.base/java.lang.Integer.parseInt(Integer.java:654)
at java.base/java.lang.Integer.parseInt(Integer.java:784)
at HelloKt.main(Hello.kt:5)
at HelloKt.main(Hello.kt)
Process finished with exit code 1
Here is what I am trying to do, I want the user to enter whatever number and it should be displayed, but I am getting this error.
import java.util.*
This is my code
fun main(){
print("Enter your age")
var age = readLine()!!.toInt()
print(age)
}
And the error I am getting is
Enter your age 40
Exception in thread "main" java.lang.NumberFormatException: For input string: " 40"
at java.base/java.lang.NumberFormatException.forInputString(NumberFormatException.java:67)
at java.base/java.lang.Integer.parseInt(Integer.java:654)
at java.base/java.lang.Integer.parseInt(Integer.java:784)
at HelloKt.main(Hello.kt:5)
at HelloKt.main(Hello.kt)
Process finished with exit code 1
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您正在在40的前面编写一个空间，如错误“ 40”所示。
解决方案可能是将所有领先和尾随的空间从阅读线中进行修剪，例如：
You are writing a space in front of the 40 as indicated by the error " 40".
A solution could be is to trim all leading and trailing whitespaces from the readLine, like this: