如何在Javafx和JFXML中绑定Vbox的度假胜地儿童

Question

我有包括网格窗格和Vbox在内的FXML代码，其中包含具有IDS的按钮，

它可以绑定Vbox，以便根据FX：ID求解按钮的顺序？

<?xml version="1.0" encoding="UTF-8"?>

<?import javafx.scene.control.Button?>
<?import javafx.scene.layout.ColumnConstraints?>
<?import javafx.scene.layout.GridPane?>
<?import javafx.scene.layout.RowConstraints?>
<?import javafx.scene.layout.VBox?>

<GridPane maxHeight="-Infinity" maxWidth="-Infinity" minHeight="-Infinity" minWidth="-Infinity" prefHeight="472.0" prefWidth="698.0" xmlns:fx="http://javafx.com/fxml/1" xmlns="http://javafx.com/javafx/18">
  <columnConstraints>
    <ColumnConstraints hgrow="SOMETIMES" minWidth="10.0" prefWidth="100.0" />
    <ColumnConstraints hgrow="SOMETIMES" minWidth="10.0" prefWidth="100.0" />
  </columnConstraints>
  <rowConstraints>
    <RowConstraints minHeight="10.0" prefHeight="30.0" vgrow="SOMETIMES" />
  </rowConstraints>
   <children>
      <VBox prefHeight="200.0" prefWidth="100.0" GridPane.columnIndex="1">
         <children>
            <Button fx:id="1" mnemonicParsing="false" prefHeight="72.0" prefWidth="350.0" text="1" />
            <Button fx:id="2" mnemonicParsing="false" prefHeight="72.0" prefWidth="350.0" text="2" />
            <Button fx:id="3" mnemonicParsing="false" prefHeight="72.0" prefWidth="350.0" text="3" />
            <Button fx:id="4" mnemonicParsing="false" prefHeight="72.0" prefWidth="350.0" text="4" />
            <Button fx:id="5" mnemonicParsing="false" prefHeight="72.0" prefWidth="350.0" text="5" />
            <Button fx:id="6" mnemonicParsing="false" prefHeight="72.0" prefWidth="350.0" text="6" />
            <Button fx:id="7" mnemonicParsing="false" prefHeight="72.0" prefWidth="350.0" text="7" />
         </children>
      </VBox>
   </children>
</GridPane>

控制器 控制器具有

        @FXML
            public void initialize() {
List<Integer> ids = new ArrayList<>();        // resort the childs of vbox based on the list "ids"
    
    }

我想将按钮列表绑定到我的“ IDS”变量，该变量包括新的FX-ID，如果列表 - 元素的顺序更改，则还应更改Vbox内部按钮列表的顺序

Answer 1

0
更好地使用来自SortedMap接口的treemap。

SortedMap<Integer, CheckBox> sm = TreeMap<Integer, CheckBox>();

sm.put(new Integer(1),new CheckBox("first checkbox"));
sm.put(new Integer(2),new CheckBox("second checkbox"));
sm.put(new Integer(3),new CheckBox("third checkbox"));
sm.put(new Integer(4),new CheckBox("fourth checkbox"));
sm.put(new Integer(5),new CheckBox("fifth checkbox"));
sm.put(new Integer(6),new CheckBox("sixth checkbox"));
sm.put(new Integer(7),new CheckBox("seventh checkbox"));
....

按照ID的顺序进行遍历后获得它们