Selenium Start-n-with搜索整个页面未在给定的Webelement中

发布于 2025-02-10 13:54:13 字数 1540 浏览 2 评论 0原文

我想在特定的webelement中搜索与start-with的类名称，但它在整个页面中搜索。我不知道怎么了。

如果webelement中的此HTML列表（ One_row ）返回

muidatagrid_rows = driver.find_elements(by=By.CLASS_NAME, value='MuiDataGrid-row')
one_row = muidatagrid_rows[0]

此html作品，

<div class="market-watcher-title_os_button_container__4-yG+">
    <div class="market-watcher-title_tags_container__F37og"></div>
    <div>
        <a href="#" target="blank" rel="noreferrer" data-testid="ios download button for 1628080370">
        <img class="apple-badge-icon-image"></a>
    </div>
    <div></div>
</div>

如果有这样的完整类名称的搜索：

tags_and_marketplace_section = one_row.find_element(by=By.CLASS_NAME, value="market-watcher-title_os_button_container__4-yG+")

它给出了错误：

selenium.common.exceptions.InvalidSelectorException: Message: Given css selector expression ".market-watcher-title_os_button_container__4-yG+" is invalid: InvalidSelectorError: Element.querySelector: '.market-watcher-title_os_button_container__4-yG+' is not a valid selector: ".market-watcher-title_os_button_container__4-yG+"

所以我想使用starting-with-with方法搜索，但我无法获得我想要的东西。这应该仅返回两个插话，但它返回20

tags_and_marketplace_section = one_row.find_element(by=By.XPATH, value='//div[starts-with(@class, "market-watcher-")]')
print(len(tags_and_marketplace_section))
>>> 20

原文

I want to search class name with starts-with in specific Webelement but it search in entire page. I do not know what is wrong.

This returns list

muidatagrid_rows = driver.find_elements(by=By.CLASS_NAME, value='MuiDataGrid-row')
one_row = muidatagrid_rows[0]

This HTML piece in WebElement (one_row)

<div class="market-watcher-title_os_button_container__4-yG+">
    <div class="market-watcher-title_tags_container__F37og"></div>
    <div>
        <a href="#" target="blank" rel="noreferrer" data-testid="ios download button for 1628080370">
        <img class="apple-badge-icon-image"></a>
    </div>
    <div></div>
</div>

If a search with full class name like this:

tags_and_marketplace_section = one_row.find_element(by=By.CLASS_NAME, value="market-watcher-title_os_button_container__4-yG+")

It gives error:

selenium.common.exceptions.InvalidSelectorException: Message: Given css selector expression ".market-watcher-title_os_button_container__4-yG+" is invalid: InvalidSelectorError: Element.querySelector: '.market-watcher-title_os_button_container__4-yG+' is not a valid selector: ".market-watcher-title_os_button_container__4-yG+"

So i want to search with starts-with method but i can not get what i want.
This should returns only two Webelements but it returns 20

tags_and_marketplace_section = one_row.find_element(by=By.XPATH, value='//div[starts-with(@class, "market-watcher-")]')
print(len(tags_and_marketplace_section))
>>> 20

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澉约 2025-02-17 13:54:13

在不看到代码库的情况下，您很难完全提供帮助，但是我发现“链接”值可以帮助缩小返回的结果。另外，使用“ by.css_selector”方法最适合我。

例如，如果您想要的是在DIV和P内，那么您将做类似的事情。

driver.find_elements(by=By.CSS_SELECTOR, value="div #MuiDataGrid-row p")

然后，您可以处理如您所描述的返回的元素。您也许可以使用其他方法/选择器，但这是我到目前为止最喜欢的路线。

Without seeing the codebase you are scraping from it's difficult to help fully, however what I've found is that "Chaining" values can help to narrow down the returned results. Also, using the "By.CSS_SELECTOR" method works best for me.

For example, if what you want is inside a div and p, then you would do something like this;

driver.find_elements(by=By.CSS_SELECTOR, value="div #MuiDataGrid-row p")

Then you can work with the elements that are returned as you described. You maybe able to use other methods/selectors but this is my favourite route so far.

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