如何在Python中传递函数中的字符串，该功能使用库CTYPES从CPP导出

Question

我正在导出函数加密的cpp代码段，该函数在下面的参数，

#include <iostream>
using namespace std;

string Function(char* str) 
{
    
    string temp = str;
    int length = temp.length();
    
    int disp = length,i=0;
    char printChar;
    
    char *store = (char *)malloc(sizeof(char)*100);
    while(disp > 0) {
        printChar = *(str + length - disp);
        if ((printChar >= 65) && (printChar <= 90)) {
            if (printChar+disp > 90) {
                printChar = ((printChar+disp) % 90) + 64;
                store[i] = printChar;
                
            }else{
                printChar += disp;
                store[i] = printChar;
                
            };
        }
        else if ((printChar >= 97) && (printChar <= 122)) {
            if (printChar+disp > 122) {
                printChar = ((printChar+disp) % 122) + 96;
                store[i] = printChar;
                
            }else{
                printChar += disp;
                store[i] = printChar;
                  
            };
        }
        else {
            store[i] = printChar;
            
        };
        disp -= 1;
        i += 1;
    };
    return store;
}
// The part where i am exporting
extern "C" {
    string encrypt(char* str) // this is the functionName(in this case encrypt) which i am giving when exporting
    {
        return Function(str);
    }
}

我应该在我的python代码下传递此导出函数中的字符串有点像：

userString = input()
result = encrypt(userstring) // this is function created in cpp
print(result)

我不知道如何正确使用ctypes。那么请有人可以帮助解决这个问题吗？