使用Gmail API的Google云平台项目：为桌面应用程序创建令牌
范围：我想通过python和raspbery pi/raspian或Windows 10上的Gmail访问我的Gmail。
之后官方指南 Google我创建了一个项目，并启用了Gmail API，根据本指南对于桌面应用程序，下载并将其重命名为recertentials.json running quickStart.py我得到我获得的正如预期的：
＆gt;＆gt;＆gt; ＃获取Gmail API服务
...服务= gmail_authenticate（）
请访问此URL以授权此应用程序：https://accounts.google.com/o/oauth22 /auth?Response_type=code&Client_id= [xxx.apps.googleusercontent.com＆amp; rediRect_uri = http%3A%3A%2F%2FlocalHost%3a34551; state = [xxx]＆amp; access_type = offline
在浏览器中打开URL时：
我关注链接到 unsafe ：
并获取localhost的链接：
http：// localhost：34551/？state state state state state state state state = [xxx]＆amp; code = [xxx]＆amp; scope = https：//mail.google.com/
问题： 如何获得应用程序授权 /获取client_secret.json < / code>等？
Scope: I want to access my Gmail via python and the Gmail API on Raspbery pi /Raspian or Windows 10.
Following the official guide from Google I created a project and enabled the Gmail API, Authorization credentials for a desktop application according to this guide for Desktop app, downloaded it and renamed it to credentials.json when running quickstart.py I get as expected:
>>> # get the Gmail API service
... service = gmail_authenticate()
Please visit this URL to authorize this application: https://accounts.google.com/o/oauth2/auth?response_type=code&client_id=[XXX.apps.googleusercontent.com]&redirect_uri=http%3A%2F%2Flocalhost%3A34551%2F&scope=https%3A%2F%2Fmail.google.com%2F&state=[xxx]&access_type=offline
When opening the URL in the browser:
I follow the link to unsafe:
and get the link to localhost:
http://localhost:34551/?state=[XXX]&code=[XXX]&scope=https://mail.google.com/
Question:
How can I get the app authorized / get the client_secret.json, etc?
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安装XAMPP解决了问题。
在这种情况下，Windows II不起作用
Installing xampp solved the issue.
The windows IIS did not work in this case