如何通过不确切的文本JS过滤

发布于 2025-02-10 12:42:03 字数 719 浏览 1 评论 0原文

这是Ag-Grid JS代码的一部分，该代码具有准确的文本过滤单元格：

function doesExternalFilterPass(node) {
  switch (status) {
    case 'released':
      return node.data.Status == 'Released';
    case 'early-access':
      return node.data.Status == 'Early access';
    case 'in-development':
      return node.data.Status == 'In development';
    case 'rtt-strategy':
      return node.data.Genre == /.'RTT'./;
    default:
      return true;
  }
}

例如，其中一个字符串过滤了所有包含在状态列中的发行的单元，而其他包含 rtt 的单元在流派柱中。 ，但是我需要像 rtt，rts，action 这样的字符串也要过滤。据我了解，我应该使用正则表达式，我尝试此操作，

return node.data.Genre == /.'RTT'./;

但它不起作用。

有什么想法可以进行多个字的过滤？

原文

Here is a part of ag-grid JS code that filter cells with exactly text:

function doesExternalFilterPass(node) {
  switch (status) {
    case 'released':
      return node.data.Status == 'Released';
    case 'early-access':
      return node.data.Status == 'Early access';
    case 'in-development':
      return node.data.Status == 'In development';
    case 'rtt-strategy':
      return node.data.Genre == /.'RTT'./;
    default:
      return true;
  }
}

For example, one of the strings filter all cells containing Released in Status column, other containing RTT in Genre column. But I need that strings like RTT, RTS, Action also to be filtered. As I understand, I should use regular expressions, I try this

return node.data.Genre == /.'RTT'./;

but it doesn't work.

Any ideas to get many-words filtering?

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愁以何悠 2025-02-17 12:42:03

您不需要正则是这样。如果可能的话，应避免正则。如果我正确理解，您要检查字符串是否包含子字符串。为此，您可以使用string.prototype.includes（）方法： https://developer.mozilla.org/en-us/docs/web/javascript/reference/reference/global_objects/string/includes
示例代码：

case 'rtt-strategy':
  return node.data.Genre.includes('RTT');

如果您仍然要使用Regex，则可以使用Regexp.prototype.test（）方法： https://develoverer.mozilla.org/en-us/docs/web/web/javas/javascript/javascript/reference/reference/global_obal_obableds/global_obignts/regex/regexplestestest < /a>。首先，您确实应该查找如何在JS中使用Regex，因为您的示例代码已经遥遥无期。其次，示例代码：

/RTT/.test(node.data.Genre)

或者如果您要病例不敏感，则：

/RTT/i.test(node.data.Genre)

You don't need regex for this. Regex should be avoided, if possible. If I understand it correctly, you want to check if a string contains a substring. For that you can use String.prototype.includes() method: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/includes
Example code:

case 'rtt-strategy':
  return node.data.Genre.includes('RTT');

If you still want to use regex, then you can use the RegExp.prototype.test() method: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/RegExp/test. First of all, you really should look up how to use regex in js, because your example code is way off. Secondly, example code: