在引号之间提取subtring，但跳过\;并将其变成”而是在卢阿

Question

我有这样的字符串

"argument \\\" \"some argument\" \"some argument with a quotation mark \\\" in here \""

，它可以打印出来

argument \" "some argument" "some argument with a quotation mark \" in here"

，并且我正在尝试提取所有字符串，以便最后存储这样的存储：

> [1] = "argument",
> [2] = """,
> [3] = "some argument",
> [4] = "some argument with a quotation mark " in here"

这是我到目前为止的代码。

function ExtractArgs(text)
    local skip = 0
    local arguments = {}
    local curString = ""

    for i = 1, text:len() do
        if (i <= skip) then continue end

        local c = text:sub(i, i)
        
        if (c == "\\") and (text:sub(i+1, i+1) == "\"") then
            continue
        end
        
        if (c == "\"") and (text:sub(i-1, i-1) ~= "\\") then
            local match = text:sub(i):match("%b\"\"")
            
            if (match) and (match:sub(#match-1,#match-1) ~= "\\") then
                curString = ""
                skip = i + #match
                arguments[#arguments + 1] = match:sub(2, -2)
            else
                curString = curString..c
            end
        elseif (c == " " and curString ~= "") then
            arguments[#arguments + 1] = curString
            curString = ""
        else
            if (c == " " and curString == "") then
                continue
            end

            curString = curString..c
        end
    end

    if (curString ~= "") then
        arguments[#arguments + 1] = curString
    end
    
    return arguments
end

print(ExtractArgs("argument \\\" \"some argument\" \"some argument with a quotation mark \\\" in here\""))

的报价标记之间不是，但不是在引号之间

它正确提取\“正确

。 “ \\]*（？：\\。[^\“ \\]*）*）\” ，但是lua呢？

Answer 1

该任务无法使用单个LUA模式完成，但可以通过几种模式来实现。
文本参数不得包含字节\ 0，\ 1和\ 2 - 这些特殊字符用于临时替代。

local function ExtractArgs(text)
   local arguments = {}
   for argument in 
      ('""'..text:gsub("\\?.", {['\\"']="\1"}))
      :gsub('"(.-)"([^"]*)', function(q,n) return "\2"..q..n:gsub("%s+", "\0") end)
      :sub(2)
      :gmatch"%Z+" 
   do
      argument = argument:gsub("\1", '"'):gsub("\2", ""):gsub("\\(.)", "%1")
      print(argument)
      arguments[#arguments+1] = argument
   end   
   return arguments
end

ExtractArgs[[argument \"\\ "" "some argument" "some argument with a quotation mark \" in here \\"]]

输出：

argument
"\

some argument
some argument with a quotation mark " in here \