使用PYQT 5从.QML文件获取单选按钮值

Question

如何使用PYQT 5从.QML文件获取单选按钮值？

.QML文件如下：

import QtQuick 2.15
import QtQuick.Controls 2.15

ApplicationWindow {
    visible: true
    width: 600
    height: 500
    title: "HelloApp"

    RadioButton {
        id: button1
        text: "1"
        objectName: "radio_button"
    }

    TextInput {
        id: text_input
        objectName: "Textinput"
        x:300
        y:300
        width: 80
        height: 20
    }

    Button {
        id: button_execute
        x: 158
        y: 341
        width: 211
        height: 36
        text: qsTr("Execute")
        onClicked: {
            con.on_execute()
        }
    }
}

用于读取此.QML文件的Python代码如下：

import sys
from os.path import abspath, dirname, join
from PyQt5.QtGui import QGuiApplication
from PyQt5.QtQml import QQmlApplicationEngine
from PyQt5.QtCore import QObject, pyqtSlot


class Bridge(QObject):
    @pyqtSlot()
    def on_execute(self):
        win = engine.rootObjects()[0]
        # This will give me the value of text input
        text_val = win.findChild(QObject, "Textinput").property("text")
        # How to get the radio button value if it's checked or not checked?

app = QGuiApplication(sys.argv)
if __name__ == '__main__':
    # Reading the qml file
    engine = QQmlApplicationEngine()
    context = engine.rootContext()
    bridge = Bridge()
    context.setContextProperty("con", bridge)
    qmlFile = join(dirname(__file__), 'qml_test_1.qml')
    engine.load(abspath(qmlFile))

    if not engine.rootObjects():
        sys.exit(-1)

    sys.exit(app.exec_())

我如何知道是否检查了单个单选按钮？我尝试使用对象名称。但这不起作用。

Answer 1

不要使用对象名称。这是不好的做法。使用信号，插槽或型号。

---

示例：

file main.py

import sys
from os.path import abspath, dirname, join
from PyQt5.QtGui import QGuiApplication
from PyQt5.QtQml import QQmlApplicationEngine
from PyQt5.QtCore import QObject, pyqtSlot


class App(QObject):
    def __init__(self, parent=None):
        super().__init__(parent)
        self.current_rb_text = ""

    @pyqtSlot(str)
    def set_current_rb_text(self, text: str):
        self.current_rb_text = text

    @pyqtSlot()
    def on_execute(self):
        print(self.current_rb_text)

app = QGuiApplication(sys.argv)
if __name__ == '__main__':
    # Reading the qml file
    engine = QQmlApplicationEngine()
    context = engine.rootContext()
    bridge = App()
    context.setContextProperty("App", bridge)
    qmlFile = join(dirname(__file__), 'main.qml')
    engine.load(abspath(qmlFile))

    if not engine.rootObjects():
        sys.exit(-1)

    sys.exit(app.exec_())

file myradiobutton.qml

import QtQuick 2.15
import QtQuick.Controls 2.15


RadioButton {id:btn
    onClicked:App.set_current_rb_text(btn.text)
}

file main.qml

import QtQuick 2.15
import QtQuick.Controls 2.15
import QtQuick.Layouts 1.14

ApplicationWindow {
    visible: true
    width: 600
    height: 500
    title: "HelloApp"

    ColumnLayout{
        MyRadioButton {
            id: button1
            text: "1"
            objectName: "radio_button"
        }

        MyRadioButton {
            id: button2
            text: "2"
            objectName: "radio_button"
        }

        MyRadioButton {
            id: button3
            text: "3"
            objectName: "radio_button"
        }
    }

    TextInput {
        id: text_input
        objectName: "Textinput"
        x:300
        y:300
        width: 80
        height: 20
    }

    Button {
        id: button_execute
        x: 158
        y: 341
        width: 211
        height: 36
        text: qsTr("Execute")
        onClicked: {
             App.on_execute()
        }
    }

}

注意：

我建议您使用pyside6.3，因为它是官方QT绑定，它可以更好地支持 qml 。例如，在这里，您可能只是在Python中声明了一个属性，并将其绑定到“无线电”按钮文本。