为什么可以“ typescript”无宽恕的操作员（！）处于下一行的开头？

发布于 2025-02-10 04:07:51 字数 419 浏览 1 评论 0 原文

以下代码无法在带有或不带有括号的打字稿中编译（）：

const foo: string | undefined = undefined;

const a = ("something very long and take all this line"
    as any);

const b = (foo // Could be something very long as well
    !.toString());

有趣的是，没有！。，， .toString（）甚至？。

为什么会发生这种情况？假设代码样式每行具有最大的字符，我该如何将其移至新行？我尝试将它们包裹在括号（）或将 \ 放在行结尾时，无效。

原文

The following code cannot be compiled in TypeScript with or without the parentheses ():

const foo: string | undefined = undefined;

const a = ("something very long and take all this line"
    as any);

const b = (foo // Could be something very long as well
    !.toString());

Interestingly, without the !., .toString() or even ?.toString() would work well on the new line.

Why is this happening? Assuming a code style that has maximum character per line, how do I move these to the new line? I have tried wrapping them in parentheses () or put a \ at the end of the line, none works.