JSON必须如何将MongoDB迫使Bindata子类型4

发布于 2025-02-09 23:36:59 字数 612 浏览 2 评论 0原文

我正在使用C＃驱动程序mongodb.driver 2.16.0 我正在尝试插入纯JSON。我希望_id用作新的UUID类型AKA Bindata subtype 4。但是我只能得到Subtype 3或纯字符串。

var testColl = db.GetCollection<BsonDocument>("test");
var testJson = "[{'_id':CSUUID('609e26f6-dbad-4dba-ba37-4e35f0e348ec'),'name':'Data1'},{'_id':CSUUID('609e26f6-dbad-4dba-ba37-4e35f0e348ff'),'name':'Data2'}]";
testColl.InsertMany(BsonSerializer.Deserialize<BsonDocument[]>(testJson));

我尝试了'_id'：'609E26F6-DBAD-4DBA-BA37-4E35F0E348EC'，导致字符串。
我尝试了'_id'：uuid（'609e26f6-dbad-4dba-ba37-4e35f0e348ec'），在Subtype 3中进行了混音。

示例代码还会导致

子类型3。

原文

I'm using the c# driver MongoDB.Driver 2.16.0
I'm trying to insert pure json.
I want the _id to be used as the new UUID type aka BinData subtype 4. But I get only subtype 3 or pure string.

var testColl = db.GetCollection<BsonDocument>("test");
var testJson = "[{'_id':CSUUID('609e26f6-dbad-4dba-ba37-4e35f0e348ec'),'name':'Data1'},{'_id':CSUUID('609e26f6-dbad-4dba-ba37-4e35f0e348ff'),'name':'Data2'}]";
testColl.InsertMany(BsonSerializer.Deserialize<BsonDocument[]>(testJson));

I tried '_id':'609e26f6-dbad-4dba-ba37-4e35f0e348ec' which results in a string.
I tried '_id':UUID('609e26f6-dbad-4dba-ba37-4e35f0e348ec') which rusults in subtype 3.
And the example code also results in subtype 3.

How must the json look to make a subtype 4?

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北座城市 2025-02-16 23:36:59

您有以下选项：

配置bsondefaults.guidrepresentationmode = guidrePresentationMode.v3;。在这种情况下，您将使用文档中指定的子类型（或通过属性在最后查看文档）。如果是csuuid - ，那么子类型为3，uuid -4。

配置guidserialization.unspecified。例如，在收集期间创建：

  db.getCollection＆lt; bsondocument＆gt;（
    “ coll”， 
    new Mongocollectionsettings（）{guidRepresentation = guidRepresentation.unspecified}）;

这种情况类似于＃1，我们从文档中获得了子类型，但仅适用于特定集合

配置guid> guidserialization.standard强迫使用此特定集合的子类型，无论subtype在文档中提供：

  var coll = db.getCollection＆lt; bsondocument＆gt;（“ coll”，new mongocollectionsettings（）{guidrePresentation = guidrepresentation.standard}）;
var testjson =“ [{'_id'：csuuID（'609e26f6-dbad-4dba-ba37-4e37-4e35f0e348ec'），'name'：'data1'}，{'_ id'} 4E35F0E348FF'），'名称'：'data2'}]”;
Coll.InsertMany（bsonserializer.deserialize＆lt; bsondocument []＆gt;（testjson））; //插入子类型为4（UUID/标准）

您还可以在全球范围内配置GuidRepresentation： bsondefaults.guidrepresentation = guidrepresentation.standard;。在这种情况下，您将默认情况下强制使用此表示形式（对于guidrepresentationmode.v2默认模式），

您可以找到详细信息在这里

You have the following options:

Configure BsonDefaults.GuidRepresentationMode = GuidRepresentationMode.V3;. In this case, you will work with subTypes specified in the document (or via attributes see the doc in the end). If it's CSUUID - then subType is 3, UUID - 4.

Configure GuidSerialization.Unspecified. For example during collection creating:

db.GetCollection<BsonDocument>(
    "coll", 
    new MongoCollectionSettings() { GuidRepresentation = GuidRepresentation.Unspecified});

this case is similar to #1 where we get used subType from a document, but only for a particular collection

Configuring GuidSerialization.Standard to force using this particular subType for a collection regardless a subType provided in the document:

var coll = db.GetCollection<BsonDocument>("coll", new MongoCollectionSettings() { GuidRepresentation = GuidRepresentation.Standard});
var testJson = "[{'_id':CSUUID('609e26f6-dbad-4dba-ba37-4e35f0e348ec'),'name':'Data1'},{'_id':CSUUID('609e26f6-dbad-4dba-ba37-4e35f0e348ff'),'name':'Data2'}]";
coll.InsertMany(BsonSerializer.Deserialize<BsonDocument[]>(testJson)); // inserted subType is 4 (UUID/Standard)

You also can configure GuidRepresentation globally like: BsonDefaults.GuidRepresentation = GuidRepresentation.Standard;. In this case you will force using this representation by default everywhere (for GuidRepresentationMode.V2 which is default mode)

You can find details here

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