我可以在jupyter中使用for循环打印饼图吗？

Question

我需要用于循环来在功能中（最好是水平的）打印多个饼图。我的假设是，如果我使用for循环打印饼图，将产生所有图表，但结果将垂直显示。但是，只显示了最后一个数字。

import matplotlib.pyplot as plt
for i in range(3):
    labels = ['part_1','part_2','part_3']
    pie_portions = [5,6,7]
    plt.pie(pie_portions,labels=labels,autopct = '%1.1f%%')
    plt.title(f'figure_no : {i+1}')

Answer 1

您正在遇到jupyter笔记本中内置的depl范式，用于最后引用的对象。 print （和/或在笔记本的情况下显示）在“ read-evaluate-print loop'（depp）默认情况下，通常仅适用于jupyter在输出中。这与为什么您具有定义变量的原因有关，您可以将其调用为单元的最后一行，并且它的值将显示在而无需 print（my_variable）。

关于您的假设。要使它们都显示垂直，请尝试：

import matplotlib.pyplot as plt
for i in range(3):
    labels = ['part_1','part_2','part_3']
    pie_portions = [5,6,7]
    plt.pie(pie_portions,labels=labels,autopct = '%1.1f%%')
    plt.title(f'figure_no : {i+1}')
    plt.show()

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此处的所有代码块都是开发出来的，并且将在您的浏览器中正常工作，而无需通过 mybinder-sessions通过此处启动 环境由此列表 pip安装的软件包。这些特定示例中未使用其中的许多。

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基于iPywidgets Hbox的水平解决方案

此初始示例的大部分是基于调整我的答案在这里，单独 widget tabs 然后可以选择以查看以查看反过来。

import matplotlib.pyplot as plt
import pandas as pd
import numpy as np
import ipywidgets as widgets
from ipywidgets import HBox
out1 = widgets.Output()
out2 = widgets.Output()
out3 = widgets.Output()
out = HBox(children = [out1, out2, out3])

data1 = pd.DataFrame(np.random.normal(size = 50))
data2 = pd.DataFrame(np.random.normal(size = 100))
data3 = pd.DataFrame(np.random.normal(size = 104))

display(out)

with out1:
    fig1, axes1 = plt.subplots()
    data1.hist(ax = axes1)
    plt.title("test 1")
    plt.show(fig1)

with out2:
    fig2, axes2 = plt.subplots()
    data2.hist(ax = axes2)
    plt.title("test 2")
    plt.show(fig2)

with out3:
    fig3, axes3 = plt.subplots()
    data3.hist(ax = axes3)
    plt.title("test 3")
    plt.show(fig3)

这将使用Hbox并排显示三个直方图。它还使用以下方法中更多使用的子图，并且可以在不使用小部件的情况下完成工作。 （我想将小部件包含在一个选项中，它显示了我已经拥有的框架的“选项卡”显示代码如何轻松地适应Hbox代码，我可以想象，如果您使用的是使用仪表板小部件也涉及。）
但是，OP想要派。这是一个更接近我对PIE图的解决方案。但是，我发现它是故障的，需要解决方法：

import matplotlib.pyplot as plt
import ipywidgets as widgets
from ipywidgets import HBox
out1 = widgets.Output()
out2 = widgets.Output()
out3 = widgets.Output()
out4 = widgets.Output()
out = HBox(children = [out1, out2, out3, out4])

display(out)

with out1:
    labels = ['part_1','part_2','part_3']
    pie_portions = [5,6,7]
    my_plot = plt.pie(pie_portions,labels=labels,autopct = '%1.1f%%')
    plt.title('figure_no :1')

with out2:
    labels = ['part_1','part_2','part_3']
    pie_portions = [5,6,7]
    my_plot = plt.pie(pie_portions,labels=labels,autopct = '%1.1f%%')
    plt.show(my_plot)
    plt.title('figure_no :2')

with out3:
    labels = ['part_1','part_2','part_3']
    pie_portions = [5,6,7]
    my_plot3 = plt.pie(pie_portions,labels=labels,autopct = '%1.1f%%')
    plt.show(my_plot3)
    plt.title('figure_no :3')

# Easiest way to get three to display was to put a dummy one that doesn't display because of `plt.close()`,
# based on https://www.adamsmith.haus/python/answers/how-to-hide-a-figure-from-being-shown-in-matplotlib-in-python
# Otherwise, it messes up third one. This way it only messes up the one it doesn't show.
# I'm not quite sure what causes this apparent glitch, but this is a nice workaround for now. 
with out4:
    my_plot4 = plt.pie(pie_portions,labels=labels,autopct = '%1.1f%%')
    plt.show(my_plot4)
    plt.title(' ')
    plt.close()

不确定为什么从该代码中出现明显的小故障，添加第四个虚拟派情节允许所有三个馅饼地块至少可以显示。但是，这并不理想，我发现如果您将子图（请参见下文）与小部件输出相结合，那么它可以并排显示三个派图，而无需进行解决方法。通过将子图与小窗口组合结合到无实际解决的清洁版本：

import matplotlib.pyplot as plt
import pandas as pd
import numpy as np
import ipywidgets as widgets
from ipywidgets import HBox
out1 = widgets.Output()
out2 = widgets.Output()
out3 = widgets.Output()
out = HBox(children = [out1, out2, out3])

with out1:
    fig1, axes1 = plt.subplots()
    labels = ['part_1','part_2','part_3']
    pie_portions = [5,6,7]
    my_plot = plt.pie(pie_portions,labels=labels,autopct = '%1.1f%%')
    plt.title('figure_no :1')
    plt.show(my_plot)

with out2:
    fig2, axes2 = plt.subplots()
    my_plot2 = plt.pie(pie_portions,labels=labels,autopct = '%1.1f%%')
    plt.title('figure_no :2')
    plt.show(my_plot2)

with out3:
    fig3, axes3 = plt.subplots()
    my_plot3 = plt.pie(pie_portions,labels=labels,autopct = '%1.1f%%')
    plt.title('figure_no :3')
    plt.show(my_plot3)

display(out)

基于matplotlib的子图的水平解决方案

。这是从中改编的三个并排进行的：

#Using subplots based on https://matplotlib.org/stable/gallery/pie_and_polar_charts/pie_demo2.html
import matplotlib.pyplot as plt

# Some data
labels = 'Frogs', 'Hogs', 'Dogs', 'Logs'
fracs = [15, 30, 45, 10]

# Make figure and axes
fig, axs = plt.subplots(1, 3)

# A standard pie plot
axs[0].pie(fracs, labels=labels, autopct='%1.1f%%', shadow=True)

# Shift the second slice using explode
axs[1].pie(fracs, labels=labels, autopct='%.0f%%', shadow=True,
              explode=(0, 0.1, 0, 0))

# Another standard pie plot
axs[2].pie(fracs, labels=labels, autopct='%1.2f%%', shadow=False);

一个概括为像您这样的循环的概括：

import matplotlib.pyplot as plt
# Make figure and axes
fig, axs = plt.subplots(1, 3)

for i in range(3):
    labels = ['part_1','part_2','part_3']
    pie_portions = [5,6,7]
    axs[i].pie(pie_portions,labels=labels,autopct = '%1.1f%%')
    axs[i].title.set_text(f'figure_no : {i+1}') #title for subplots based on https://stackoverflow.com/a/39133654/8508004

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请注意，这些解决方案是用剧情/情节对象的活动“内存”形式进行的。您也可以将图作为图像文件保存为图像文件，并使用HTML与＆lt; img Align一起在笔记本单元中并排显示结果图像。 href =“ https://stackoverflow.com/a/44969840/8508004”>在这里and 在这里基于在这里。 （在笔记本中并排显示图像的方法被回收在这里来自图像文件集合的幻灯片。）