实验嵌套的元组。：为什么这说这是太多的变量？

发布于 2025-02-09 19:39:51 字数 307 浏览 1 评论 0原文

目前，我正在阅读有关嵌套元素的信息，并尝试了一个非常简单的元素。有人可以指出我出错的地方吗？

albums = ("Backstreet Boys", "1991", 
          [("No place"), ("Backstreet's Back"), ("Everybody")])

for artist,year,songs in albums:
    print("Artist: {}\nYear:{}\nSongs: {}".format((artist,year,songs)))

感谢您的帮助，大家。 :)

原文

I'm reading about nested tuples at the moment and trying a very simple one. Can someone point out to where I'm going wrong?

albums = ("Backstreet Boys", "1991", 
          [("No place"), ("Backstreet's Back"), ("Everybody")])

for artist,year,songs in albums:
    print("Artist: {}\nYear:{}\nSongs: {}".format((artist,year,songs)))

Thanks for the help, everyone. :)

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你又不是我 2025-02-16 19:39:51

您需要将专辑元组包裹在列表中，然后在格式命令中删除括号。

albums = [("Backstreet Boys", "1991", 
          [("No place"), ("Backstreet's Back"), ("Everybody")])]

for artist,year,songs in albums:
    print("Artist: {}\nYear:{}\nSongs: {}".format(artist,year,songs))

那是因为Xou尝试通过元组专辑迭代，而不是元组列表。

You need to wrap the albums tuple in a list and remove the brackets in the format command.

albums = [("Backstreet Boys", "1991", 
          [("No place"), ("Backstreet's Back"), ("Everybody")])]

for artist,year,songs in albums:
    print("Artist: {}\nYear:{}\nSongs: {}".format(artist,year,songs))

That is because xou try to iterate through the tuple albums, not a list of tuples.

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