我有一个字符串名称，可以包括以下可能性，我希望使用Regex表达式以相应的下划线删除字符串的X部分，并仅获取文件名。
字符串的可能性名称：
- XXX_XXX_FILENAME
- XXX_FILENAME
请注意，X是大写，仅由字母{Az}组成。我还能有一个以下的正则表达式，也可以用下划线删除X零件吗？
I have a string name that can include the following possiblities and I wish to use a regex expression to remove that X part of the string with its corresponding underscore and obtain the filename only.
Possibilities of string name:
- XXX_XXX_filename
- XXX_filename
kindly note that X is an uppercase and consists of alphabets {A-Z} only. Can i have a regex that removes the X parts with the underscore as well?
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您可以重复1或2次匹配1或更多大写字符[AZ]，然后进行下划线。
在替换中使用一个空字符串。
You can repeat 1 or 2 times matching 1 or more uppercase chars [A-Z] followed by an underscore.
In the replacement use an empty string.
Regex demo
您可以尝试以下操作：
“ xxx_xxx_filename” .replace（/^[a-z _]*/g，“”）如果您知道可以限制Regexp的总字符数：
<代码>“ xxx_xxx_filename” .replace（/^[a-z _] {3,7}/g，“”）
如果您也知道上限的组总数，则可以使用此ALOS：
“ xxx_xxx_filename” .replace（/^（[az]+_？？）{0,2}/g，“”）You can try this:
"XXX_XXX_filename".replace(/^[A-Z_]*/g,"")If you know the number of total characters you can restrict the regexp a bit more:
"XXX_XXX_filename".replace(/^[A-Z_]{3,7}/g,"")If you also know the total number of groups for upper case you could use this alos:
"XXX_XXX_Filename".replace(/^([A-Z]+_?){0,2}/g,"")