如何使用Pydantic模式与SQLalchemy关系分别列
我有4个表:硬件
,softwarename
,softwareVersion
和软件
。
软件
表具有与
关系。最后,softwarename
表和SoftwareVersion
表的一对多硬件
模型具有与
关系。软件
表的一对多
我正在尝试使用Pydantic Schema
获得模型关系中的特定列。
现在我将获得此输出:
[
{
"id": 1,
"hostname": "hostname2",
"softwares": [
{
"id": 1,
"software_name": {
"id": 1,
"name": "nginx"
},
"software_version": {
"id": 1,
"version": "2.9"
}
},
{
"id": 2,
"software_name": {
"id": 2,
"name": "vim"
},
"software_version": {
"id": 2,
"version": "0.3"
}
},
{
"id": 3,
"software_name": {
"id": 3,
"name": "apache"
},
"software_version": {
"id": 3,
"version": "1.0"
}
}
]
}
]
但是我期望的是输出:
[
{
"id": 1,
"hostname": "hostname2",
"softwares": [
{
"id": 1,
"name": "nginx",
"version": "2.9"
},
{
"id": 2,
"name": "vim",
"version": "0.3"
},
{
"id": 3,
"name": "apache",
"version": "1.0"
}
]
}
]
我有文件main.py
:
import uvicorn
from typing import Any, Iterator, List, Optional
from faker import Faker
from fastapi import Depends, FastAPI
from pydantic import BaseModel
from sqlalchemy import Column, ForeignKey, Integer, String, create_engine
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy.orm import Session, sessionmaker, relationship
from faker.providers import DynamicProvider
software_name = DynamicProvider(
provider_name="software_name",
elements=["bash", "vim", "vscode", "nginx", "apache"],
)
software_version = DynamicProvider(
provider_name="software_version",
elements=["1.0", "2.9", "1.1", "0.3", "2.0"],
)
hardware = DynamicProvider(
provider_name="hardware",
elements=["hostname1", "hostname2", "hostname3", "hostname4", "hostname5"],
)
fake = Faker()
# then add new provider to faker instance
fake.add_provider(software_name)
fake.add_provider(software_version)
fake.add_provider(hardware)
engine = create_engine("sqlite:///.db", connect_args={"check_same_thread": False})
SessionLocal = sessionmaker(autocommit=True, autoflush=True, bind=engine)
Base = declarative_base(bind=engine)
class Software(Base):
__tablename__ = 'software'
id = Column(Integer, primary_key=True)
hardware_id = Column(Integer, ForeignKey('hardware.id'))
name_id = Column(Integer, ForeignKey('software_name.id'))
version_id = Column(Integer, ForeignKey('software_version.id'))
software_name = relationship('SoftwareName', backref='software_name')
software_version = relationship('SoftwareVersion',
backref='software_version')
class SoftwareName(Base):
__tablename__ = 'software_name'
id = Column(Integer, primary_key=True)
name = Column(String)
class SoftwareVersion(Base):
__tablename__ = 'software_version'
id = Column(Integer, primary_key=True)
version = Column(String)
class Hardware(Base):
__tablename__ = "hardware"
id = Column(Integer, primary_key=True, autoincrement=True)
hostname = Column(String, nullable=False)
softwares = relationship(Software)
Base.metadata.drop_all()
Base.metadata.create_all()
class BaseSchema(BaseModel):
id: int
class Config:
orm_mode = True
class SoftwareNameSchema(BaseSchema):
name: str
class SoftwareVersionSchema(BaseSchema):
version: str
class SoftwareSchema(BaseSchema):
software_name: SoftwareNameSchema
software_version: SoftwareVersionSchema
class HardwareOut(BaseSchema):
hostname: str
softwares: List[SoftwareSchema]
app = FastAPI()
@app.on_event("startup")
def on_startup() -> None:
session = SessionLocal()
for _ in range(10):
software_list = []
for _ in range(3):
sn = SoftwareName(name=fake.software_name())
sv = SoftwareVersion(version=fake.software_version())
s = Software(software_name=sn, software_version=sv)
software_list.append(s)
h = Hardware(hostname=fake.hardware(), softwares=software_list)
session.add(h)
session.flush()
session.close()
def get_db() -> Iterator[Session]:
db = SessionLocal()
try:
yield db
finally:
db.close()
@app.get("/hardwares", response_model=List[HardwareOut])
def get_hardwares(db: Session = Depends(get_db)) -> Any:
return [HardwareOut.from_orm(hardware) for hardware in db.query(Hardware).all()]
如何更改hardwareout
架构以返回我期望的东西?
I have 4 tables: Hardware
, SoftwareName
, SoftwareVersion
, and Software
.
The Software
table has an one-to-many
relationship with SoftwareName
table and SoftwareVersion
table. Finally, the Hardware
model has an one-to-many
relationship with Software
table.
I'm trying to get just a specific column from a model relationship using Pydantic Schema
.
Now I'm getting this output:
[
{
"id": 1,
"hostname": "hostname2",
"softwares": [
{
"id": 1,
"software_name": {
"id": 1,
"name": "nginx"
},
"software_version": {
"id": 1,
"version": "2.9"
}
},
{
"id": 2,
"software_name": {
"id": 2,
"name": "vim"
},
"software_version": {
"id": 2,
"version": "0.3"
}
},
{
"id": 3,
"software_name": {
"id": 3,
"name": "apache"
},
"software_version": {
"id": 3,
"version": "1.0"
}
}
]
}
]
But what I expect is this output:
[
{
"id": 1,
"hostname": "hostname2",
"softwares": [
{
"id": 1,
"name": "nginx",
"version": "2.9"
},
{
"id": 2,
"name": "vim",
"version": "0.3"
},
{
"id": 3,
"name": "apache",
"version": "1.0"
}
]
}
]
I have the file main.py
:
import uvicorn
from typing import Any, Iterator, List, Optional
from faker import Faker
from fastapi import Depends, FastAPI
from pydantic import BaseModel
from sqlalchemy import Column, ForeignKey, Integer, String, create_engine
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy.orm import Session, sessionmaker, relationship
from faker.providers import DynamicProvider
software_name = DynamicProvider(
provider_name="software_name",
elements=["bash", "vim", "vscode", "nginx", "apache"],
)
software_version = DynamicProvider(
provider_name="software_version",
elements=["1.0", "2.9", "1.1", "0.3", "2.0"],
)
hardware = DynamicProvider(
provider_name="hardware",
elements=["hostname1", "hostname2", "hostname3", "hostname4", "hostname5"],
)
fake = Faker()
# then add new provider to faker instance
fake.add_provider(software_name)
fake.add_provider(software_version)
fake.add_provider(hardware)
engine = create_engine("sqlite:///.db", connect_args={"check_same_thread": False})
SessionLocal = sessionmaker(autocommit=True, autoflush=True, bind=engine)
Base = declarative_base(bind=engine)
class Software(Base):
__tablename__ = 'software'
id = Column(Integer, primary_key=True)
hardware_id = Column(Integer, ForeignKey('hardware.id'))
name_id = Column(Integer, ForeignKey('software_name.id'))
version_id = Column(Integer, ForeignKey('software_version.id'))
software_name = relationship('SoftwareName', backref='software_name')
software_version = relationship('SoftwareVersion',
backref='software_version')
class SoftwareName(Base):
__tablename__ = 'software_name'
id = Column(Integer, primary_key=True)
name = Column(String)
class SoftwareVersion(Base):
__tablename__ = 'software_version'
id = Column(Integer, primary_key=True)
version = Column(String)
class Hardware(Base):
__tablename__ = "hardware"
id = Column(Integer, primary_key=True, autoincrement=True)
hostname = Column(String, nullable=False)
softwares = relationship(Software)
Base.metadata.drop_all()
Base.metadata.create_all()
class BaseSchema(BaseModel):
id: int
class Config:
orm_mode = True
class SoftwareNameSchema(BaseSchema):
name: str
class SoftwareVersionSchema(BaseSchema):
version: str
class SoftwareSchema(BaseSchema):
software_name: SoftwareNameSchema
software_version: SoftwareVersionSchema
class HardwareOut(BaseSchema):
hostname: str
softwares: List[SoftwareSchema]
app = FastAPI()
@app.on_event("startup")
def on_startup() -> None:
session = SessionLocal()
for _ in range(10):
software_list = []
for _ in range(3):
sn = SoftwareName(name=fake.software_name())
sv = SoftwareVersion(version=fake.software_version())
s = Software(software_name=sn, software_version=sv)
software_list.append(s)
h = Hardware(hostname=fake.hardware(), softwares=software_list)
session.add(h)
session.flush()
session.close()
def get_db() -> Iterator[Session]:
db = SessionLocal()
try:
yield db
finally:
db.close()
@app.get("/hardwares", response_model=List[HardwareOut])
def get_hardwares(db: Session = Depends(get_db)) -> Any:
return [HardwareOut.from_orm(hardware) for hardware in db.query(Hardware).all()]
How can I change the HardwareOut
Schema to return what I expect?
如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。

绑定邮箱获取回复消息
由于您还没有绑定你的真实邮箱,如果其他用户或者作者回复了您的评论,将不能在第一时间通知您!
发布评论
评论(1)
我终于得到了我想要的答案。
我添加了2个更改以获取它:
使用
Union
从键入
属性 libsoftware> software_name
esoftware> software_version
代码>这样:添加pydantic
验证器
为每个字段更改返回的值,例如:答案是:
更新:
作为改进,我为每个属性添加一个别名,以获得更好的语义响应。因此,我将
software_name
更改为name
和software_version
版本
。像这样:I finally got the answer I wanted.
I added 2 changes to get it:
Use the
Union
type fromtyping
lib for the attributessoftware_name
esoftware_version
like that:Add a Pydantic
validator
for each field to change the returned value, like that:And the answer was this:
update:
As an improvement, I add an alias for each attribute for a better semantic response. So, I change
software_name
toname
andsoftware_version
toversion
. Like this: