Scala Spark：如何比较两个元组清单

发布于 2025-02-09 03:26:46 字数 628 浏览 2 评论 0原文

我想发现我的第一个阵列中的每个元组是否存在于我的第二个元组中。如果不是这种情况，我想返回所有与不匹配的元组以及元素的哪个元素完全不匹配。

可能是：对于firstArray中的每个元素（x，y）：对于secondarray中的每个元素（k，z）：如果（x！= k）打印（某物）返回（x，y）如果（y！= z）打印（某物）返回（x，y）示例：

val firstArray: Array[(String,String)] = Array(("elem1","elem2"), ("elem3","elem4"))
val secondArray: Array[(String,String)] = Array(("elem1","elem2"), ("elem5","elem4"), ("elem3","elem7"))

所需的输出 输出：

("elem3","elem4") is eliminated because elem4 doesn't match elem7
    val result: Array[(String,String)] = Array(("elem3","elem4"))

原文

I would like to find if each Tuple in my firstArray exists in my secondArray of tuple.
If it is not the case, i would like to return all tuple that doesn't match and which element of tuple exactly doesn't match.

It could be something like :
for each element (x,y) in firstArray:
for each element (k,z) in secondArray:
if (x != k) print(something)
return (x,y)
if (y != z) print(something)
return (x,y)
Example:

val firstArray: Array[(String,String)] = Array(("elem1","elem2"), ("elem3","elem4"))
val secondArray: Array[(String,String)] = Array(("elem1","elem2"), ("elem5","elem4"), ("elem3","elem7"))

Desired output
Output:

("elem3","elem4") is eliminated because elem4 doesn't match elem7
    val result: Array[(String,String)] = Array(("elem3","elem4"))

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只有一腔孤勇 2025-02-16 03:26:46

您可以尝试类似的内容

val res = firstArray.filterNot(secondArray.contains(_))

将返回第二个数组中不存在的第一个数组的元素。

编辑

以下代码将在两个阵列上循环，并比较元组

for {
  (i,j) <- firstArray
  (k,l) <- secondArray
}
{
  println((i,j) match {
    case (a,b) if (a == k && b ==l) => "Tuple found"
    case (a,_) if (a == k)=> "First elem only found."
    case (_,b) if (b ==l)=> "Second elem only found."
    case _ => "No match"
  })
}

希望这会有所帮助

you can try something like

val res = firstArray.filterNot(secondArray.contains(_))

It will return the elements of first array that are not present in the second.

Edit

The following code will loop over the two arrays, and compare the tuples

for {
  (i,j) <- firstArray
  (k,l) <- secondArray
}
{
  println((i,j) match {
    case (a,b) if (a == k && b ==l) => "Tuple found"
    case (a,_) if (a == k)=> "First elem only found."
    case (_,b) if (b ==l)=> "Second elem only found."
    case _ => "No match"
  })
}

Hope this will help

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