阻止对象在pygame中的故障

Question

我正在尝试使用Pygame这样的游戏，我目前有两个矩形，但是一个故障，我不知道为什么，我评论了 win.fill（（（0，0，0，0）），它停止了一个在毛刺中的矩形中，但另一个不是我所拥有的：

# import pygame module in this program
import pygame

# activate the pygame library .
# initiate pygame and give permission
# to use pygame's functionality.
pygame.init()

# create the display surface object
# of specific dimension..e(500, 500).
win = pygame.display.set_mode((1280, 720))

# set the pygame window name
pygame.display.set_caption("Pong")

# object1 current co-ordinates
x = 15
y = 280
# object2 current co-ordinates
x1 = 1245
y1 = 280
# dimensions of the object1
width = 20
height = 130
# dimensions of the object2
width1 = 20
height1 = 130
# velocity / speed of movement
vel = 10

# Indicates pygame is running
run = True

# infinite loop
while run:
    # creates time delay of 10ms
    pygame.time.delay(0)

    # iterate over the list of Event objects
    # that was returned by pygame.event.get() method.
    for event in pygame.event.get():

        # if event object type is QUIT
        # then quitting the pygame
        # and program both.
        if event.type == pygame.QUIT:

            # it will make exit the while loop
            run = False
    # stores keys pressed
    keys = pygame.key.get_pressed()

    # if left arrow key is pressed
    if keys[pygame.K_w] and y > 0:

        # decrement in y co-ordinate
        y -= vel

    # if left arrow key is pressed
    if keys[pygame.K_s] and y < 720-height:
        # increment in y co-ordinate
        y += vel

    # completely fill the surface object
    # with black colour
    win.fill((0, 0, 0))
    # drawing object on screen which is rectangle here
    pygame.draw.rect(win, (0, 0, 255), (x, y, width, height))

    # it refreshes the window
    pygame.display.update()

    keys2 = pygame.key.get_pressed()

    # if left arrow key is pressed
    if keys2[pygame.K_UP] and y1 > 0:

        # decrement in y co-ordinate
        y1 -= vel

    # if left arrow key is pressed
    if keys2[pygame.K_DOWN] and y1 < 720-height:
        # increment in y co-ordinate
        y1 += vel

    # completely fill the surface object
    # with black colour
    win.fill((0, 0, 0))

    # drawing object on screen which is rectangle here
    pygame.draw.rect(win, (255, 255, 255), (x1, y1, width1, height1))

    # it refreshes the window
    pygame.display.update()

# closes the pygame window
pygame.quit()

Answer 1

调用 pygame.display.update（）在应用程序循环结束时仅一次。多个调用 pygame.display.update（）或 pygame.display.flip（）引起闪烁。参见为什么pygame动画是闪烁的。也只清除显示一次。
实际上，您实际上是在 对象。如果您借鉴了与PyGame显示器关联的 surface ，则在显示屏中不立即可见。更改将可见，当显示显示使用 pygame.display.update（） 或 pygame.display.flip（） 。
如果清除显示屏，则所有先前绘制的元素都变得不可见。因此，在框架开始时清除显示器一次，然后在框架末端进行一次更新。

典型的pygame应用程序循环必须：

• 限制每秒帧以限制 pygame.time.clock.tick
• 通过调用 pygame.event.pump（） 或 pygame.event.get（） 。
• 更新依赖于输入事件和时间（分别框架）的对象的游戏状态和位置
• 清除整个显示或绘制背景
• 绘制整个场景（ BLIT 所有对象）
• 通过调用任何一个来更新显示器或 ）

clock = pygame.time.Clock()
run = True

# application loop
while run:
    # limit the frames per second to limit CPU usage
    clock.tick(100)

    # handle the events    
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False

    # update the game states and positions of objects
    keys = pygame.key.get_pressed()
    if keys[pygame.K_w] and y > 0:
        y -= vel
    if keys[pygame.K_s] and y < 720-height:
        y += vel
    if keys[pygame.K_UP] and y1 > 0:
        y1 -= vel
    if keys[pygame.K_DOWN] and y1 < 720-height:
        y1 += vel

    # clear the display
    win.fill((0, 0, 0))

    # draw the entire scene
    pygame.draw.rect(win, (0, 0, 255), (x, y, width, height))
    pygame.draw.rect(win, (255, 255, 255), (x1, y1, width1, height1))

    # update the display
    pygame.display.update()