QlikView-基于计数条件的计数

发布于 2025-02-09 02:59:04 字数 601 浏览 2 评论 0原文

我有下表。

order_number
100
101
101
102
103
103
103
104
104

我想创建一个表达式,该表达式计算order_number仅发生一次的实例。 示例-100和102不重复,而101、103和104具有多个实例。 预期的结果是2。

我尝试了 count({< count(order_number)= {1}>} order_number) 但似乎不起作用。

也尝试使用AGGR count((({< aggr)(count(order_number),order_number))= {1}>} order_number)

I have the following table.

order_number
100
101
101
102
103
103
103
104
104

I'd like to create an expression which counts instances where order_number occurs only once.
Example - 100 and 102 do not repeat, while 101, 103 and 104 have multiple instances.
The expected result is 2.

I've tried
count({<count(order_number)={1}>}order_number)
but does not seem to work.

Tried using Aggr too
count(({<Aggr(count(order_number), order_number))={1}>}order_number)

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评论(1

心的憧憬 2025-02-16 02:59:04

(可能不是很有效的方法)

sum(if(aggr(count(order_number),order_number),order_number)= 1、1、0))

(从内部到外)

  • aggr(count(count_number)) ,order_number) - will count每个order_number 的实例
  • if(... = 1,1,1,0) - for每个order_number如果内部(count)计算等于1,则返回1 else 0 0
  • sum(...)所有这些

和结果(在文本框中)

“结果”

如果可能的话(取决于您的要求)在脚本中标记这些记录。之后,表达式将非常简单(有效)

(Probably not very efficient way)

sum( if( aggr( count( order_number ), order_number) = 1, 1, 0 ) )

(from inside to outside)

  • aggr( count( order_number ), order_number) - will count the instances of each order_number
  • if( ... = 1, 1, 0) - for each order_number if the inner (count) calculation is equal to 1 then return 1 else 0
  • and sum(...) all of this

And the result (in the textbox)

result

If possible (depends on your requirement) flag these records in the script. After that the expression will be much simple (and efficient)

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