完成100％完成时更改进度栏文本

Question

在此示例中，总进度为5秒（我正在构建一个可延展的模型，我可以使用任何可以使用相同的总数的秒数）：

from rich.progress import Progress
import time
import sys

def main(timeout):
    start_time = time.time()

    penultimate_quarter = timeout-1
    with Progress() as progress:
        task1 = progress.add_task("[green]Processing...", total=100)
        while not progress.finished:
            progress.update(task1, advance=100/penultimate_quarter)
            time.sleep(1)
        time.sleep(1)
        progress.update(task1, description="[blue]Complete Task", advance=100)

    print("--- %s seconds ---" % (time.time() - start_time))

if __name__ == "__main__":
    main(5)

output（同一行）：

但是我想要的输出不包含此100％带有消息处理...：

​progress.fineded用我可以将其放入已经传递了多少个价值的方法并暂停了循环，例如：

penultimate_quarter = timeout-1
while progress.total_advance <= (penultimate_quarter/timeout):
    # rest of code...

我如何根据 rich 用法？

Answer 1

修改1：对象值定义总进度

之前：

total=100
advance=100/penultimate_quarter
advance=100

After：

total=timeout
advance=timeout/penultimate_quarter
advance=timeout

修改2：time.sleep之前的位置和使用

之前：after：

penultimate_quarter = timeout-1
with Progress() as progress:
    task1 = progress.add_task("[green]Processing...", total=100)
    while not progress.finished:
        progress.update(task1, advance=100/penultimate_quarter)
        time.sleep(1)
    time.sleep(1)
    progress.update(task1, description="[blue]Complete Task", advance=100)

after：

penultimate_quarter = timeout-1
with Progress() as progress:
    task1 = progress.add_task("[green]Processing...", total=timeout)
    time.sleep(1)
    while not progress.finished:
        time.sleep(1)
        progress.update(task1, advance=timeout/penultimate_quarter)
    progress.update(task1, description="[blue]Complete Task", advance=timeout)

最终代码：

from rich.progress import Progress
import time
import sys

def main(timeout):
    start_time = time.time()

    penultimate_quarter = timeout-1
    with Progress() as progress:
        task1 = progress.add_task("[green]Processing...", total=timeout)
        time.sleep(1)
        while not progress.finished:
            time.sleep(1)
            progress.update(task1, advance=timeout/penultimate_quarter)
        progress.update(task1, description="[blue]Complete Task", advance=timeout)

    print("--- %s seconds ---" % (time.time() - start_time))

if __name__ == "__main__":
    main(5)

输出（更新同一行）：