如何拆分矩阵，然后使用JavaScript显示其最小值和最大值？

Question

我有一个矩阵，

const matrix = [
      [1,5,7],
      [7,3,5],
      [2,6,9]
];

我想将其分成子量表，

[
 [1,5],
 [7,3]
]
[
 [5,7],
 [3,5]
]
[
 [7,3],
 [2,6]
]
[
 [3,5],
 [6,9]
]

中获取最大值

[
 [7,7],
 [7,9]
]

然后我想从子词和最小值

[
  [1,3],
  [2,3]
]

。我该如何处理？

Answer 1

由于未指定原始矩阵的尺寸和子膜的尺寸，因此我以示例中给出的尺寸：

// main function
public static void functionMatrix() {
    int[][] matrix = {{1, 5, 7}, {7, 3, 5}, {2, 6, 9}};

    int[][] matrixResultMax = new int[matrix.length - 1][matrix[0].length - 1];
    int[][] matrixResultMin = new int[matrix.length - 1][matrix[0].length - 1];

    for (int i = 0; i < matrix.length - 1; i++) {
        for (int j = 0; j < matrix[i].length - 1; j++) {
            //Submatrix elements
            System.out.println("[");
            System.out.println("[ " + matrix[i][j] + ", " + matrix[i][j + 1] + " ],");
            System.out.println("[ " + matrix[i + 1][j] + ", " + matrix[i + 1][j + 1] + " ]");
            matrixResultMax[i][j] = Math.max(Math.max(matrix[i][j], matrix[i][j + 1]), Math.max(matrix[i + 1][j], matrix[i + 1][j + 1]));
            matrixResultMin[i][j] = Math.min(Math.min(matrix[i][j], matrix[i][j + 1]), Math.min(matrix[i + 1][j], matrix[i + 1][j + 1]));
            System.out.println("]");
        }
    }

    printMatrix(matrixResultMax);
    printMatrix(matrixResultMin);
}

//new Function
public static void printMatrix(int[][] matr) {
    for (int[] ints : matr) {
        for (int anInt : ints) {
            System.out.print(anInt + " ");
        }
        System.out.println();
    }
}