i=input - storing the function in i to be called later
zip(i(),i()) - if the user entered 1010 and 1101, this would return [(1, 1), (0, 1), (1, 0), (0, 1)] - the elements of both strings paired up
for a,b in - a and b are the pair from the zip (in the example they are first set to a=1 and b=1, then a=0 and b=1, etc.)
'01'[a!=b] - a!=b will return a boolean - either True or False. True = 1 and False = 0 so you can use this for indexing. Basically this says if a!=b: '1', if a==b: '0'
''.join - finally, join all the '0's and '1's together to make one string and print
发布评论
评论（2）
逐步说明：
i = input- 将函数存储在i中，以后称为zip（i（），i（），i（））-如果用户输入1010和1101，这将返回[（1，1），（0，1），（1，1，0），（0，（0，（0，） 的两个字符串的元素是来自1）] - in a a 和
bzip（在示例中，它们首先设置为a = 1和b = 1，然后a = 0和b = 1等）'01'[a！= b] < /code> -a！= b将返回布尔值 - 是的。true= 1和false= 0，因此您可以将其用于索引。基本上，这说明如果A！= B：'1'，如果a == b：'0''''。join- 最后，最后，将所有“ 0和1”一起加入一个字符串并打印Explained step by step:
i=input- storing the function inito be called laterzip(i(),i())- if the user entered1010and1101, this would return[(1, 1), (0, 1), (1, 0), (0, 1)]- the elements of both strings paired upfor a,b in-aandbare the pair from thezip(in the example they are first set to a=1 and b=1, then a=0 and b=1, etc.)'01'[a!=b]-a!=bwill return a boolean - either True or False.True= 1 andFalse= 0 so you can use this for indexing. Basically this saysif a!=b: '1',if a==b: '0'''.join- finally, join all the '0's and '1's together to make one string and print如果您真的想将其制作为Oneliner，请删除分号并这样做：
zip用元组创建一个值，所以“ HI”和“ HO”将成为[（h，h），（i，o）][a！= b]确实，它评估true（1）或false（0），''。加入串联列表中的所有元素，然后将其打印If you really want to make it a oneliner, remove the semicolon and do it like this:
zipcreates an iterable with tuples, so "hi" and "ho" will become [(h,h), (i,o)][a!=b]does, it evaluates to eitherTrue(1) orFalse(0)''.joinconcatenates all elements in your list, and this gets printed