找不到Python网站的正确XPath

发布于 2025-02-08 18:38:36 字数 1045 浏览 2 评论 0原文

我正在尝试从 https： //www.reuters.com/markets/companies/aali.jk/key-metrics/per-share-data 对于EPS的数据，XPath中的EPS标准化（年度）1,010.14。请单击“ cybe scortshot”

https://i.sstatic.net/gnfrn.png 从Inspect中，我使用XPATH如下所示，但返回['1,833.60'，'741.35'，'113.12'，'1,702.00'，'1.0498'，'1.2223'，'1.2223'，'0.0074' '1.667'，'-0.029'，'2.493'，'-0.007'，'0.42'，'+0.195'，'3,674.84'，'3,438.46'，'3,438.46'，'7,016.25正确的数据。

from lxml import html
import requests

page= requests.get('https://www.reuters.com/markets/companies/AALI.JK/key-metrics/per-share-data')
data = html.fromstring(page.content)
data.xpath('//td/span/text()')

如何在强大的代码中获得EPS标准化（年度）1,010.14？

原文

I am trying to get the data from https://www.reuters.com/markets/companies/AALI.JK/key-metrics/per-share-data
for data of the EPS Normalized (Annual) 1,010.14 in xpath.
Kindly click for the inspect screenshot

https://i.sstatic.net/gnFrN.png
From inspect, I use xpath as below but return ['1,833.60', '741.35', '113.12', '1,702.00', '1.0498', '1.2223', '0.0074', '0.1489', '3.231', '1.667', '-0.029', '2.493', '-0.007', '0.42 ', '+0.195', '3,674.84', '3,438.46', '7,016.25', '25,963.00'] which is not the correct data.

from lxml import html
import requests

page= requests.get('https://www.reuters.com/markets/companies/AALI.JK/key-metrics/per-share-data')
data = html.fromstring(page.content)
data.xpath('//td/span/text()')

How may I get EPS Normalized (Annual) 1,010.14 in a robust code?

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夏有森光若流苏 2025-02-15 18:38:36

本网站使用JavaScript加载其内容，

因此，如果您要使用Selenium，则可以使用此

搜索th标记文本“ EPS BASIC DERVEN。父/..，您将获得其余的

// th [contains（text（），“ eps basic dept。

如果不是，并且想处理请求，以下是一个临时解决方案

import requests, re
from lxml import html

page = requests.get('https://www.reuters.com/markets/companies/AALI.JK/key-metrics/per-share-data')

data = html.fromstring(page.content)

txt = data.xpath('//*[@id="fusion-metadata"]/text()')[0]

eps_norm_annual = float(re.search('"eps_normalized_annual":"([0-9.]+)"', txt).group(1))

This site uses JavaScript to load its content,

so if you're going to use selenium you can use this

Search for the th tag with the text "EPS Basic Excl. Extra Items (Annual)" then get the parent /.. and you get the rest

//th[contains(text(), "EPS Basic Excl. Extra Items (Annual)")]/../td/span

if not and want to work with requests, here is a temporary solution

import requests, re
from lxml import html

page = requests.get('https://www.reuters.com/markets/companies/AALI.JK/key-metrics/per-share-data')

data = html.fromstring(page.content)

txt = data.xpath('//*[@id="fusion-metadata"]/text()')[0]

eps_norm_annual = float(re.search('"eps_normalized_annual":"([0-9.]+)"', txt).group(1))

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