snakemake：如何对glob_wildcards（）排序
如何使用glob_wildcards（）以字母顺序获取文件？
假设我在同一目录中有Sample1.txt，Sample2.txt，Sample3.txt和Sample4.txt。 当我运行此代码时：
file_pattern = 'dir_test/{sample}.txt'
FILES = glob_wildcards(file_pattern)
SAMPLES = FILES.sample
rule all:
input:
expand(file_pattern, sample=SAMPLES),
"concat.txt"
rule concat:
input:
expand("dir_test/{sample}.txt", sample=SAMPLES),
output:
"concat.txt"
shell:
"""
cat {input} > {output}
"""
我得到了glob_wildcards（）的结果，按照以下任意顺序出现：
$ cat concat.txt
This is Sample4
This is Sample1
This is Sample2
This is Sample3
How can I get files in alphabetical order using glob_wildcards()?
Suppose I have sample1.txt, sample2.txt, sample3.txt, and sample4.txt in the same directory.
When I run this code:
file_pattern = 'dir_test/{sample}.txt'
FILES = glob_wildcards(file_pattern)
SAMPLES = FILES.sample
rule all:
input:
expand(file_pattern, sample=SAMPLES),
"concat.txt"
rule concat:
input:
expand("dir_test/{sample}.txt", sample=SAMPLES),
output:
"concat.txt"
shell:
"""
cat {input} > {output}
"""
I got the results of glob_wildcards() come out in an arbitrary order as follows:
$ cat concat.txt
This is Sample4
This is Sample1
This is Sample2
This is Sample3
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评论（1）
您是否尝试过类似：（
不确定
list（）甚至是必要的）。Have you tried something like:
(not sure that
list()is even necessary).