MKTime返回-1，但有效数据
我尝试为默认日期找到一种方法（如果日期不有效）。 通用方法正常工作：
set(2022,6,17,12,12,0,0,0)
void KTime::Set(int nYear, int nMonth, int nDay, int nHour, int nMin, int nSec, int nDST, bool isUTC)
{
assert(nYear >= 1900);
assert(nMonth >= 1 && nMonth <= 12);
assert(nDay >= 1 && nDay <= 31);
assert(nHour >= 0 && nHour <= 23);
assert(nMin >= 0 && nMin <= 59);
assert(nSec >= 0 && nSec <= 59);
struct tm atm;
atm.tm_sec = nSec;
atm.tm_min = nMin;
atm.tm_hour = nHour;
atm.tm_mday = nDay;
atm.tm_mon = nMonth - 1; // tm_mon is 0 based
atm.tm_year = nYear - 1900; // tm_year is 1900 based
atm.tm_isdst = nDST;
m_time = isUTC ? utc_mktime(&atm) : mktime(&atm);
assert(m_time != -1); // indicates an illegal input time
}
但是，如果我设置为相同的功能：
set(1900,1,1,0,0,0,0,0)
我会得到一个mktime = -1 知道我的逻辑炸弹在哪里？
I try to find a way for a default date (if date is not valid).
Common way works fine:
set(2022,6,17,12,12,0,0,0)
void KTime::Set(int nYear, int nMonth, int nDay, int nHour, int nMin, int nSec, int nDST, bool isUTC)
{
assert(nYear >= 1900);
assert(nMonth >= 1 && nMonth <= 12);
assert(nDay >= 1 && nDay <= 31);
assert(nHour >= 0 && nHour <= 23);
assert(nMin >= 0 && nMin <= 59);
assert(nSec >= 0 && nSec <= 59);
struct tm atm;
atm.tm_sec = nSec;
atm.tm_min = nMin;
atm.tm_hour = nHour;
atm.tm_mday = nDay;
atm.tm_mon = nMonth - 1; // tm_mon is 0 based
atm.tm_year = nYear - 1900; // tm_year is 1900 based
atm.tm_isdst = nDST;
m_time = isUTC ? utc_mktime(&atm) : mktime(&atm);
assert(m_time != -1); // indicates an illegal input time
}
But if I set to the same function:
set(1900,1,1,0,0,0,0,0)
I will get a mktime = -1
Any idea where is my logic bomb?
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mktime（以及POSIX日期功能的其余部分）仅适用于日期＆gt; = 1970-01-01 00:00:00， unix epoch 。mktime， quoth the Manual ，，而1900绝对不能表示为time_t，因为它早70年。
mktime(and the rest of the POSIX date functions) only work for dates >= 1970-01-01 00:00:00, the UNIX epoch.mktime, quoth the manual,and 1900 definitely can't be represented as a time_t, since it's 70 years early.