如何重命名文件（使用Python OS模块）？

发布于 2025-02-08 15:49:42 字数 435 浏览 0 评论 0原文

我有一个文件夹，其中包含+100歌曲，名为“歌曲名称，歌手名称”（例如Smooth Firster，Michael Jackson ）。我正在尝试将所有歌曲重命名为“歌曲名称（歌手名称）”（例如Smooth Primits（Michael Jackson））。

我尝试了此代码。但是，我不知道要写哪些参数。

import os

files = os.getcwd()

os.rename(files, "") # I'm confused because I don't know what to put here as parameters since I want to change only parts of the files' names, and not the files' names entirely.

关于“ os.rename（）”参数有什么建议吗？

原文

I have a folder which contains +100 songs named this way "Song Name, Singer Name" (e.g. Smooth Criminal, Michael Jackson). I'm trying to rename all the songs to "Song Name (Singer Name)" (e.g. Smooth Criminal (Michael Jackson)).

I tried this code. But, I didn't know what parameters to write.

import os

files = os.getcwd()

os.rename(files, "") # I'm confused because I don't know what to put here as parameters since I want to change only parts of the files' names, and not the files' names entirely.

Any suggestions on the parameters of "os.rename()"?

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笑饮青盏花 2025-02-15 15:49:42

与命令行程序重命名可以使用单个命令中的模式重命名的文件批次，Python的os.rename（）是围绕基础重命名 syscall。因此，它可以一次重命名一个文件。

假设所有歌曲都存储在同一目录中，并以'.mp3'之类的扩展名结尾，则一种方法是循环循环os.listdir（）。

此外，明智的做法是检查当前文件是否确实是文件，而不是目录或符号链接。可以使用os.path.isfile（）

这是一个完整的示例：

import os 

TARGET_DIR = "/path/to/some/folder"

for filename in os.listdir(TARGET_DIR):
    # Only consider regular files
    if not os.path.isfile(filename):
        continue

    # Extract filename and extension
    basename, extension = os.path.splitext(filename)
    if ',' not in basename:
        continue # Ignore

    # Extract the song and singer names
    songname, singername = basename.split(',', 1) 

    # Build the new name, rename
    target_name = f'{songname} ({singername}){extension}'
    os.rename(
        os.path.join(TARGET_DIR, filename),
        os.path.join(TARGET_DIR, target_name)
    )

Note ：如果这些歌曲可能存储在子文件夹中，则）将比较低级别os.listdir（）更好

Unlike the command line program rename which can rename a batch of files using a pattern in a single command, Python's os.rename() is a thin wrapper around the underlying rename syscall. It can thus rename a single file at a time.

Assuming all songs are stored in the same directory and ends with an extension like '.mp3', one approach is to loop over the return of os.listdir().

Additionally, it would be wise to check that current file is, indeed a file and not, say, a directory or symbolic link. This can be done using os.path.isfile()

Here is a full example:

import os 

TARGET_DIR = "/path/to/some/folder"

for filename in os.listdir(TARGET_DIR):
    # Only consider regular files
    if not os.path.isfile(filename):
        continue

    # Extract filename and extension
    basename, extension = os.path.splitext(filename)
    if ',' not in basename:
        continue # Ignore

    # Extract the song and singer names
    songname, singername = basename.split(',', 1) 

    # Build the new name, rename
    target_name = f'{songname} ({singername}){extension}'
    os.rename(
        os.path.join(TARGET_DIR, filename),
        os.path.join(TARGET_DIR, target_name)
    )

Note: If the songs are potentially stored in subfolders, os.walk() will be a better candidate than the lower level os.listdir()

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