有没有办法获得并节省乌龟的角度？

Question

我正在制作一个程序，用户可以单击屏幕3次，这是一个三角形。然后，它将找到这3行的中间点。接下来，我希望它绘制垂直于组成三角形的每条线（通过中间点）的每条线的3行。

我陷入垂直线。我想尝试保存（就像您保存一个位置或坐标一样）乌龟bob（连接三角形线的一个）的角度，然后将中间行放置海龟（l1，l2，l3）以该角度倾斜。然后，它会使它向右移动并绘制线路。很抱歉，如果这还不清楚，但是我真的无法想到另一种解释的方式。这是我的代码：

import turtle

tur = turtle.Turtle() #draws the dots
bob = turtle.Turtle() #connects the dots
l1 = turtle.Turtle() #middle point of line 1
l2 = turtle.Turtle() #middle point of line 2
l3 = turtle.Turtle() #middle point of line 3
mid = turtle.Turtle() #point where the lines cross, haven't used this one yet
screen = turtle.Screen()
screen.tracer(0,0)

screen.setup(800,800)

tur.ht()
tur.up()
tur.speed(0)
bob.ht()
bob.up()
bob.speed(0)
screen.update()

l1.up()
l2.up()
l3.up()
mid.up()
mid.ht()

dots = 1

def lines():
    line()
    l1.goto(line_1_mid_cords) #go to middle of lines
    l1.dot()
    l2.goto(line_2_mid_cords)
    l2.dot()
    l3.goto(line_3_mid_cords)
    l3.dot()

def line():
    global line_1_mid_cords, line_2_mid_cords, line_3_mid_cords
    line_1_mid_cords = (( bob_x1 + bob_x2 ) /2, ( bob_y1 + bob_y2 ) /2) #get middle coordinates
    
    line_2_mid_cords = (( bob_x2 + bob_x3 ) /2, ( bob_y2 + bob_y3 ) /2)
    
    line_3_mid_cords = (( bob_x1 + bob_x3 ) /2, ( bob_y1 + bob_y3 ) /2)
    

def dotOnClick(x,y):
    global dots, bob_x1, bob_y1, bob_x2, bob_y2, bob_x3, bob_y3
    
    if dots == 1:
        if x >= -800 and x <= 800 and y >= -800 and y <= 800: #click on screen
            tur.goto(x,y) #go to that point
            bob.goto(tur.pos())#bob goes there too
            bob_x1 = bob.xcor() #saves bobs coordinates
            bob_y1 = bob.ycor()
            tur.dot()
            bob.down()
            screen.update()
            dots = 2 
                
    elif dots == 2:
        if x >= -800 and x <= 800 and y >= -800 and y <= 800: #when second dot is clicked
            tur.goto(x,y) #both tur and bob to to that point and they get connected
            bob.goto(tur.pos())
            bob_x2 = bob.xcor()
            bob_y2 = bob.ycor()
            tur.dot() #draws second dot
            bob.down()
            screen.update()
            dots = 3
    
    elif dots == 3:
        if x >= -800 and x <= 800 and y >= -800 and y <= 800: #same for 3rd point on screen
            tur.goto(x,y)
            bob.goto(tur.pos())
            bob_x3 = bob.xcor()
            bob_y3 = bob.ycor()
            tur.dot()
            bob.down()
            bob.goto(bob_x1,bob_y1) #bob goes to first dot and completes the triangle
            lines() #makes the turtles l1, l2, l3 go to the middle points of the triangle lines
            screen.update()
            dots = 4
       
    elif dots == 4:
        if x >= -800 and x <= 800 and y >= -800 and y <= 800: #resets when you click again
            tur.clear()
            bob.clear()
            screen.update()
            tur.reset()
            bob.reset()
            tur.ht()
            tur.up()
            tur.speed(0)
            bob.ht()
            bob.up()
            bob.speed(0)
            screen.update()
            dots = 1

        
turtle.onscreenclick(dotOnClick,1,True)

如果我需要更多地解释我的含义，请这样说！

Answer 1

将您的中点海龟放在他们的位置之后，您可以将它们瞄准三角形的下一个点。

def lines():
    line()
    l1.goto(line_1_mid_cords) #go to middle of lines
    l1.setheading(l1.towards(bob_x2, bob_y2))
    l1.dot()
    l2.goto(line_2_mid_cords)
    l2.setheading(l2.towards(bob_x3, bob_y3))
    l2.dot()
    l3.goto(line_3_mid_cords)
    l3.setheading(l3.towards(bob_x1, bob_y1))
    l3.dot()