Kotlin无法识别具有字符串或递延值值的地图中的递延/承诺/未来值
val varToValue = mapOf("@id" to arg.userId, "@salary" to arg.salary)
for (variable in varToValue.keys) {
fieldData = fieldData.replace(Regex(variable),if(varToValue[variable] is String) varToValue[variable] else varToValue[variable]?.await() ?: "") //here
}
这里fieldData是一个字符串，可能包含@id或@salary。 arg.id是类型字符串和arg.salary的类型deferred＆lt; string＆gt;。现在，我调用替换功能的行无法识别等待（）调用。它给了我重命名参考的建议。基本上，我认为它无法识别它是递延类型的。我如何解决这个问题。我可以为递延和普通类型制作不同的地图，但我希望我可以解决一个循环，只有一张地图。
val varToValue = mapOf("@id" to arg.userId, "@salary" to arg.salary)
for (variable in varToValue.keys) {
fieldData = fieldData.replace(Regex(variable),if(varToValue[variable] is String) varToValue[variable] else varToValue[variable]?.await() ?: "") //here
}
Here fieldData is a string which might contain @id or @salary. arg.id is of type String and arg.salary is of type Deferred<String>. Now the line where I call the replace function is not able to identify the await() call. It is giving me the suggestion of Rename reference. Basically I think it is not able to identify that it is of Deferred type. How do i solve this problem. I can make a different map for Deferred and normal type but I was hoping I could solve in one for loop and just one map.
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当它不是
String时，可以简单地输入vartovalue [variable]。这似乎为我解决了问题。
Can simply typecast the
varToValue[variable]when it is not aString.This seems to solve the problem for me.
问题在于，Kotlin是一种强烈键入的语言，
延期＆lt; string＆gt;andstring是两种不同的类型。解决此问题的最简单方法是将它们都更改为延期，例如，wraparg.idplottabledabledebledeferred：The problem is that Kotlin is a strongly typed language and a
Deferred<String>andStringare two different types. The easiest way to solve this problem would be to change them both to beDeferred, for example, wraparg.idinto aCompletableDeferred: