从具有多个字符串元素的数组中提取数字

发布于 2025-02-08 12:12:47 字数 760 浏览 1 评论 0原文

一个阵列有4个元素。我只想打印出数千个。

my_array = ['STK72184 4/28/2022 50 from Exchange Balance, 50 from Earning Balance & 10 from Bonus 5000 Regular 10/20/2023 Approved 4/28/2022',
            'STK725721 4/27/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 5000 Regular 10/19/2023 Approved 4/27/2022',
            'STK725721 4/27/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 15000 Regular 10/19/2023 Approved 4/27/2022',
            'STK722222 4/26/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 10000 Regular 10/18/2023 Approved 4/26/2022']

预期输出为：

[‘5000’, ‘5000’, ‘15000’, ‘10000’]

原文

An array has 4 elements. I want only the the thousands to printed out.

my_array = ['STK72184 4/28/2022 50 from Exchange Balance, 50 from Earning Balance & 10 from Bonus 5000 Regular 10/20/2023 Approved 4/28/2022',
            'STK725721 4/27/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 5000 Regular 10/19/2023 Approved 4/27/2022',
            'STK725721 4/27/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 15000 Regular 10/19/2023 Approved 4/27/2022',
            'STK722222 4/26/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 10000 Regular 10/18/2023 Approved 4/26/2022']

Expected output is:

[‘5000’, ‘5000’, ‘15000’, ‘10000’]

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￡冰雨忧蓝° 2025-02-15 12:12:47

使用 re.search ，将第一匹匹配到1个或更多位数的模式，然后是3个零。

import re

my_array = ['STK72184 4/28/2022 50 from Exchange Balance, 50 from Earning Balance & 10 from Bonus 5000 Regular 10/20/2023 Approved 4/28/2022',
            'STK725721 4/27/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 5000 Regular 10/19/2023 Approved 4/27/2022',
            'STK725721 4/27/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 15000 Regular 10/19/2023 Approved 4/27/2022',
            'STK722222 4/26/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 10000 Regular 10/18/2023 Approved 4/26/2022']

# If you want strings:
nums = [re.search(r'\d+000', s)[0] for s in my_array]
print(nums)
# ['5000', '5000', '15000', '10000']

# If you want integers:
nums = [int(re.search(r'\d+000', s)[0]) for s in my_array]
print(nums)
# [5000, 5000, 15000, 10000]

Use re.search, which extract the first match to the pattern of 1 or more digit, followed by 3 zeros.

import re

my_array = ['STK72184 4/28/2022 50 from Exchange Balance, 50 from Earning Balance & 10 from Bonus 5000 Regular 10/20/2023 Approved 4/28/2022',
            'STK725721 4/27/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 5000 Regular 10/19/2023 Approved 4/27/2022',
            'STK725721 4/27/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 15000 Regular 10/19/2023 Approved 4/27/2022',
            'STK722222 4/26/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 10000 Regular 10/18/2023 Approved 4/26/2022']

# If you want strings:
nums = [re.search(r'\d+000', s)[0] for s in my_array]
print(nums)
# ['5000', '5000', '15000', '10000']

# If you want integers:
nums = [int(re.search(r'\d+000', s)[0]) for s in my_array]
print(nums)
# [5000, 5000, 15000, 10000]

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垂暮老矣 2025-02-15 12:12:47

尝试以下操作：

lines = [l.split() for l in my_array] 
[w for words in lines for w in words if w.isnumeric() and int(w) > 1000]

['5000', '5000', '15000', '10000']

Try this:

lines = [l.split() for l in my_array] 
[w for words in lines for w in words if w.isnumeric() and int(w) > 1000]

['5000', '5000', '15000', '10000']

回复收藏 0 原文

春风十里 2025-02-15 12:12:47

您可以映射一个功能，该函数将首先分配为字符串并在所需的数组中获取项目，在这种情况下：

>>> array = ['STK72184 4/28/2022 50 from Exchange Balance, 50 from Earning Balance & 10 from Bonus 5000 Regular 10/20/2023 Approved 4/28/2022',
...     'STK725721 4/27/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 5000 Regular 10/19/2023 Approved 4/27/2022',
...     'STK725721 4/27/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 15000 Regular 10/19/2023 Approved 4/27/2022',
...     'STK722222 4/26/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 10000 Regular 10/18/2023 Approved 4/26/2022']
>>> #mapping with the function
>>> thousands = list(map(lambda x:x.split()[-5],array))
>>> thousands
['5000', '5000', '15000', '10000']

you could map a function that, splits the first the string and taking the item in the array that you want, in this case:

>>> array = ['STK72184 4/28/2022 50 from Exchange Balance, 50 from Earning Balance & 10 from Bonus 5000 Regular 10/20/2023 Approved 4/28/2022',
...     'STK725721 4/27/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 5000 Regular 10/19/2023 Approved 4/27/2022',
...     'STK725721 4/27/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 15000 Regular 10/19/2023 Approved 4/27/2022',
...     'STK722222 4/26/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 10000 Regular 10/18/2023 Approved 4/26/2022']
>>> #mapping with the function
>>> thousands = list(map(lambda x:x.split()[-5],array))
>>> thousands
['5000', '5000', '15000', '10000']

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~没有更多了~