我如何转换类型但要替换类型中的每个值

发布于 2025-02-08 12:08:36 字数 1189 浏览 0 评论 0原文

只是一个进入打字稿世界的新开发人员。这似乎并不是很困难,但是我似乎找不到Google的任何解决方案,也没有堆叠自己。

我如何将/铸件类型转换为

type UsersSelect = {
    id: boolean
    created_at: boolean
    username: boolean
    discriminator: boolean
    activityMessage: boolean
    activityStatus: boolean
    userid: boolean
    lastseen: boolean
    themeId: boolean
    badges: boolean
    bannerColor: boolean
    friends: boolean
  }

type UsersSelect = {
  id: {
    public: true,
    private: true,
  },
  created_at: {
    public: true,
    private: true,
  },
  username: {
    public: true,
    private: true,
  },
  discriminator: {
    public: true,
    private: true,
  },
  activityMessage: {
    public: true,
    private: true,
  },
  userid: {
    public: false,
    private: true,
  },
  activityStatus: {
    public: true,
    private: true,
  },
  badges: {
    public: true,
    private: true,
  },
  bannerColor: {
    public: true,
    private: true,
  },
  friends: {
    public: false,
    private: true,
  },
  lastseen: {
    public: true,
    private: true,
  },
  themeId: {
    public: false,
    private: true,
  },
};

尝试了一些可能的解决方案,但所有这些似乎都没有起作用。

Just a new developer entering the typescript world. This may kinda seem not that all hard but I can't seem to find any solutions about this issue from google nor stack overflow itsself.

How do I convert/cast typescript type from

type UsersSelect = {
    id: boolean
    created_at: boolean
    username: boolean
    discriminator: boolean
    activityMessage: boolean
    activityStatus: boolean
    userid: boolean
    lastseen: boolean
    themeId: boolean
    badges: boolean
    bannerColor: boolean
    friends: boolean
  }

to

type UsersSelect = {
  id: {
    public: true,
    private: true,
  },
  created_at: {
    public: true,
    private: true,
  },
  username: {
    public: true,
    private: true,
  },
  discriminator: {
    public: true,
    private: true,
  },
  activityMessage: {
    public: true,
    private: true,
  },
  userid: {
    public: false,
    private: true,
  },
  activityStatus: {
    public: true,
    private: true,
  },
  badges: {
    public: true,
    private: true,
  },
  bannerColor: {
    public: true,
    private: true,
  },
  friends: {
    public: false,
    private: true,
  },
  lastseen: {
    public: true,
    private: true,
  },
  themeId: {
    public: false,
    private: true,
  },
};

I tried few possible solutions but all didn't seem to work.

如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。

扫码二维码加入Web技术交流群

发布评论

需要 登录 才能够评论, 你可以免费 注册 一个本站的账号。

评论(1

谁把谁当真 2025-02-15 12:08:36

这就是您的方式。您可以使用第一个类型的所有键,并使用新值类型创建记录类型({public:true,private:private:true})。

type UsersSelectConverted = Record<keyof UsersSelect, {public: true, private: true}>

Here's how you do that. You take all the keys of the first type and create a Record type with a new value type ({public: true, private: true}).

type UsersSelectConverted = Record<keyof UsersSelect, {public: true, private: true}>
~没有更多了~
我们使用 Cookies 和其他技术来定制您的体验包括您的登录状态等。通过阅读我们的 隐私政策 了解更多相关信息。 单击 接受 或继续使用网站,即表示您同意使用 Cookies 和您的相关数据。
原文